Have researches managed to “reverse time” and if so, what does that mean for physics?












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According to press releases, researchers have reversed time in a quantum computer and violated the second law of thermodynamics. What does that mean for physics? Will it allow time travel?



Further information:




  • "Arrow of time and its reversal on the IBM quantum computer" (2019-03-13)


  • "Physicists reverse time using quantum computer" (2019-03-13)











share|cite|improve this question











$endgroup$

















    4












    $begingroup$


    According to press releases, researchers have reversed time in a quantum computer and violated the second law of thermodynamics. What does that mean for physics? Will it allow time travel?



    Further information:




    • "Arrow of time and its reversal on the IBM quantum computer" (2019-03-13)


    • "Physicists reverse time using quantum computer" (2019-03-13)











    share|cite|improve this question











    $endgroup$















      4












      4








      4


      1



      $begingroup$


      According to press releases, researchers have reversed time in a quantum computer and violated the second law of thermodynamics. What does that mean for physics? Will it allow time travel?



      Further information:




      • "Arrow of time and its reversal on the IBM quantum computer" (2019-03-13)


      • "Physicists reverse time using quantum computer" (2019-03-13)











      share|cite|improve this question











      $endgroup$




      According to press releases, researchers have reversed time in a quantum computer and violated the second law of thermodynamics. What does that mean for physics? Will it allow time travel?



      Further information:




      • "Arrow of time and its reversal on the IBM quantum computer" (2019-03-13)


      • "Physicists reverse time using quantum computer" (2019-03-13)








      quantum-mechanics thermodynamics quantum-entanglement time-reversal-symmetry arrow-of-time






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      edited 2 hours ago









      knzhou

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      44.9k11122217










      asked 4 hours ago









      Omar Einstein Omar Einstein

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          2 Answers
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          15












          $begingroup$

          They did not reverse time, they reversed the "arrow of time", meaning that time continued forward but entropy decreased a little, for a moment. Small temporary violations of the second law happens spontaneously all the time on a microscopic scale, wherever the thermal energy comes together in just the right way to be absorbed into an atom or molecule. It is the same thing as "wind assembles fragments back into unbroken object" except that the macroscopic version is so unlikely as to never actually happen.



          In this case a quantum computer performed an entropy-decreasing operation. Basically they simulated one of those unlikely entropy-decreasing fluctuations, and because quantum computers utilize coherent quantum states, the simulation itself involved a decrease in entropy. But it was not a fluctuation in the quantum computer, the quantum computer was steered by careful control along the reverse path.



          This method will not be used to raise the dead, unspill cups of coffee, take back stupid actions, or any of the other practical applications of reversing the arrow of time, because it can only be applied to quantum systems that were completely under external observation and control from the beginning.






          share|cite|improve this answer









          $endgroup$













          • $begingroup$
            I think I disagree with this answer. Where is there any notion of a thermodynamic process in this paper? It looks like deterministic control of a coherent 2-qubit system, in which case entropy isn't even a sensible quantity as far as I can tell.
            $endgroup$
            – DanielSank
            54 mins ago



















          2












          $begingroup$

          It just means they can make a couple of quits go back to the state they were originally in, and they can do this in a determinable way. In that very small universe all the EM forces, and EM forces essentially determine time (like we have a gazillion or infinite number of EM forces in our universe that determine time), went to a state they had previously been in, this would be impossible in our bigger universe. No it's not time travel, its just physicists controlling a very small universe.






          share|cite|improve this answer









          $endgroup$













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            2 Answers
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            active

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            2 Answers
            2






            active

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            15












            $begingroup$

            They did not reverse time, they reversed the "arrow of time", meaning that time continued forward but entropy decreased a little, for a moment. Small temporary violations of the second law happens spontaneously all the time on a microscopic scale, wherever the thermal energy comes together in just the right way to be absorbed into an atom or molecule. It is the same thing as "wind assembles fragments back into unbroken object" except that the macroscopic version is so unlikely as to never actually happen.



            In this case a quantum computer performed an entropy-decreasing operation. Basically they simulated one of those unlikely entropy-decreasing fluctuations, and because quantum computers utilize coherent quantum states, the simulation itself involved a decrease in entropy. But it was not a fluctuation in the quantum computer, the quantum computer was steered by careful control along the reverse path.



            This method will not be used to raise the dead, unspill cups of coffee, take back stupid actions, or any of the other practical applications of reversing the arrow of time, because it can only be applied to quantum systems that were completely under external observation and control from the beginning.






            share|cite|improve this answer









            $endgroup$













            • $begingroup$
              I think I disagree with this answer. Where is there any notion of a thermodynamic process in this paper? It looks like deterministic control of a coherent 2-qubit system, in which case entropy isn't even a sensible quantity as far as I can tell.
              $endgroup$
              – DanielSank
              54 mins ago
















            15












            $begingroup$

            They did not reverse time, they reversed the "arrow of time", meaning that time continued forward but entropy decreased a little, for a moment. Small temporary violations of the second law happens spontaneously all the time on a microscopic scale, wherever the thermal energy comes together in just the right way to be absorbed into an atom or molecule. It is the same thing as "wind assembles fragments back into unbroken object" except that the macroscopic version is so unlikely as to never actually happen.



            In this case a quantum computer performed an entropy-decreasing operation. Basically they simulated one of those unlikely entropy-decreasing fluctuations, and because quantum computers utilize coherent quantum states, the simulation itself involved a decrease in entropy. But it was not a fluctuation in the quantum computer, the quantum computer was steered by careful control along the reverse path.



            This method will not be used to raise the dead, unspill cups of coffee, take back stupid actions, or any of the other practical applications of reversing the arrow of time, because it can only be applied to quantum systems that were completely under external observation and control from the beginning.






            share|cite|improve this answer









            $endgroup$













            • $begingroup$
              I think I disagree with this answer. Where is there any notion of a thermodynamic process in this paper? It looks like deterministic control of a coherent 2-qubit system, in which case entropy isn't even a sensible quantity as far as I can tell.
              $endgroup$
              – DanielSank
              54 mins ago














            15












            15








            15





            $begingroup$

            They did not reverse time, they reversed the "arrow of time", meaning that time continued forward but entropy decreased a little, for a moment. Small temporary violations of the second law happens spontaneously all the time on a microscopic scale, wherever the thermal energy comes together in just the right way to be absorbed into an atom or molecule. It is the same thing as "wind assembles fragments back into unbroken object" except that the macroscopic version is so unlikely as to never actually happen.



            In this case a quantum computer performed an entropy-decreasing operation. Basically they simulated one of those unlikely entropy-decreasing fluctuations, and because quantum computers utilize coherent quantum states, the simulation itself involved a decrease in entropy. But it was not a fluctuation in the quantum computer, the quantum computer was steered by careful control along the reverse path.



            This method will not be used to raise the dead, unspill cups of coffee, take back stupid actions, or any of the other practical applications of reversing the arrow of time, because it can only be applied to quantum systems that were completely under external observation and control from the beginning.






            share|cite|improve this answer









            $endgroup$



            They did not reverse time, they reversed the "arrow of time", meaning that time continued forward but entropy decreased a little, for a moment. Small temporary violations of the second law happens spontaneously all the time on a microscopic scale, wherever the thermal energy comes together in just the right way to be absorbed into an atom or molecule. It is the same thing as "wind assembles fragments back into unbroken object" except that the macroscopic version is so unlikely as to never actually happen.



            In this case a quantum computer performed an entropy-decreasing operation. Basically they simulated one of those unlikely entropy-decreasing fluctuations, and because quantum computers utilize coherent quantum states, the simulation itself involved a decrease in entropy. But it was not a fluctuation in the quantum computer, the quantum computer was steered by careful control along the reverse path.



            This method will not be used to raise the dead, unspill cups of coffee, take back stupid actions, or any of the other practical applications of reversing the arrow of time, because it can only be applied to quantum systems that were completely under external observation and control from the beginning.







            share|cite|improve this answer












            share|cite|improve this answer



            share|cite|improve this answer










            answered 3 hours ago









            Mitchell PorterMitchell Porter

            7,87011344




            7,87011344












            • $begingroup$
              I think I disagree with this answer. Where is there any notion of a thermodynamic process in this paper? It looks like deterministic control of a coherent 2-qubit system, in which case entropy isn't even a sensible quantity as far as I can tell.
              $endgroup$
              – DanielSank
              54 mins ago


















            • $begingroup$
              I think I disagree with this answer. Where is there any notion of a thermodynamic process in this paper? It looks like deterministic control of a coherent 2-qubit system, in which case entropy isn't even a sensible quantity as far as I can tell.
              $endgroup$
              – DanielSank
              54 mins ago
















            $begingroup$
            I think I disagree with this answer. Where is there any notion of a thermodynamic process in this paper? It looks like deterministic control of a coherent 2-qubit system, in which case entropy isn't even a sensible quantity as far as I can tell.
            $endgroup$
            – DanielSank
            54 mins ago




            $begingroup$
            I think I disagree with this answer. Where is there any notion of a thermodynamic process in this paper? It looks like deterministic control of a coherent 2-qubit system, in which case entropy isn't even a sensible quantity as far as I can tell.
            $endgroup$
            – DanielSank
            54 mins ago











            2












            $begingroup$

            It just means they can make a couple of quits go back to the state they were originally in, and they can do this in a determinable way. In that very small universe all the EM forces, and EM forces essentially determine time (like we have a gazillion or infinite number of EM forces in our universe that determine time), went to a state they had previously been in, this would be impossible in our bigger universe. No it's not time travel, its just physicists controlling a very small universe.






            share|cite|improve this answer









            $endgroup$


















              2












              $begingroup$

              It just means they can make a couple of quits go back to the state they were originally in, and they can do this in a determinable way. In that very small universe all the EM forces, and EM forces essentially determine time (like we have a gazillion or infinite number of EM forces in our universe that determine time), went to a state they had previously been in, this would be impossible in our bigger universe. No it's not time travel, its just physicists controlling a very small universe.






              share|cite|improve this answer









              $endgroup$
















                2












                2








                2





                $begingroup$

                It just means they can make a couple of quits go back to the state they were originally in, and they can do this in a determinable way. In that very small universe all the EM forces, and EM forces essentially determine time (like we have a gazillion or infinite number of EM forces in our universe that determine time), went to a state they had previously been in, this would be impossible in our bigger universe. No it's not time travel, its just physicists controlling a very small universe.






                share|cite|improve this answer









                $endgroup$



                It just means they can make a couple of quits go back to the state they were originally in, and they can do this in a determinable way. In that very small universe all the EM forces, and EM forces essentially determine time (like we have a gazillion or infinite number of EM forces in our universe that determine time), went to a state they had previously been in, this would be impossible in our bigger universe. No it's not time travel, its just physicists controlling a very small universe.







                share|cite|improve this answer












                share|cite|improve this answer



                share|cite|improve this answer










                answered 3 hours ago









                PhysicsDavePhysicsDave

                97647




                97647






























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