How to use case and filter with a group by statement and having an aggregate calculation?
I would like to do the following
SELECT
PO.col1,
PO.col2,
CASE
WHEN PO.col3 <> 8 THEN PO.col4
WHEN PO.col3 = 8 THEN CASE
WHEN (ROUND(CAST(PO.col4 AS double) - SUM(CAST(PO.col5 AS double)), 2)) > 0 AND SUM(CAST(PO.col5 AS double)) > 0
THEN ROUND(CAST(PO.col4 AS double) - SUM(CAST(PO.col5 AS double)), 2)
END
END AS Quantity
FROM
my_table AS PO
GROUP BY PO.col1, PO.col2
HAVING Quantity > 0
I apologize for not being able to provide sample data/columns. I am not allowed to share my work data.
The logic which I have been told to implement is as follows.
For each unique pair combination of col1, col2, get a constructed attribute called Quantity. Quantity = col4 wherever col3 = 8. If col3 != 8, then check SUM(col5) > 0. If yes then check col4 - SUM(col5) > 0. If yes, then keep the record, else skip.
Out of my own observation I checked that COUNT(DISTINCT col4) for each unique pair of col1 and col2 is 1. I hope that's helpful answering my question.
We are working with Spark SQL so I don't know what tag to use for this in the question.
group-by
asked 4 mins ago
scientific_explorerscientific_explorer
1
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I would like to do the following
SELECT
PO.col1,
PO.col2,
CASE
WHEN PO.col3 <> 8 THEN PO.col4
WHEN PO.col3 = 8 THEN CASE
WHEN (ROUND(CAST(PO.col4 AS double) - SUM(CAST(PO.col5 AS double)), 2)) > 0 AND SUM(CAST(PO.col5 AS double)) > 0
THEN ROUND(CAST(PO.col4 AS double) - SUM(CAST(PO.col5 AS double)), 2)
END
END AS Quantity
FROM
my_table AS PO
GROUP BY PO.col1, PO.col2
HAVING Quantity > 0
I apologize for not being able to provide sample data/columns. I am not allowed to share my work data.
The logic which I have been told to implement is as follows.
For each unique pair combination of col1, col2, get a constructed attribute called Quantity. Quantity = col4 wherever col3 = 8. If col3 != 8, then check SUM(col5) > 0. If yes then check col4 - SUM(col5) > 0. If yes, then keep the record, else skip.
Out of my own observation I checked that COUNT(DISTINCT col4) for each unique pair of col1 and col2 is 1. I hope that's helpful answering my question.
We are working with Spark SQL so I don't know what tag to use for this in the question.
group-by
asked 4 mins ago
scientific_explorerscientific_explorer
1
New contributor
scientific_explorer is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
I would like to do the following
SELECT
PO.col1,
PO.col2,
CASE
WHEN PO.col3 <> 8 THEN PO.col4
WHEN PO.col3 = 8 THEN CASE
WHEN (ROUND(CAST(PO.col4 AS double) - SUM(CAST(PO.col5 AS double)), 2)) > 0 AND SUM(CAST(PO.col5 AS double)) > 0
THEN ROUND(CAST(PO.col4 AS double) - SUM(CAST(PO.col5 AS double)), 2)
END
END AS Quantity
FROM
my_table AS PO
GROUP BY PO.col1, PO.col2
HAVING Quantity > 0
I apologize for not being able to provide sample data/columns. I am not allowed to share my work data.
The logic which I have been told to implement is as follows.
For each unique pair combination of col1, col2, get a constructed attribute called Quantity. Quantity = col4 wherever col3 = 8. If col3 != 8, then check SUM(col5) > 0. If yes then check col4 - SUM(col5) > 0. If yes, then keep the record, else skip.
Out of my own observation I checked that COUNT(DISTINCT col4) for each unique pair of col1 and col2 is 1. I hope that's helpful answering my question.
We are working with Spark SQL so I don't know what tag to use for this in the question.
group-by
asked 4 mins ago
scientific_explorerscientific_explorer
1
New contributor
scientific_explorer is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
I would like to do the following
SELECT
PO.col1,
PO.col2,
CASE
WHEN PO.col3 <> 8 THEN PO.col4
WHEN PO.col3 = 8 THEN CASE
WHEN (ROUND(CAST(PO.col4 AS double) - SUM(CAST(PO.col5 AS double)), 2)) > 0 AND SUM(CAST(PO.col5 AS double)) > 0
THEN ROUND(CAST(PO.col4 AS double) - SUM(CAST(PO.col5 AS double)), 2)
END
END AS Quantity
FROM
my_table AS PO
GROUP BY PO.col1, PO.col2
HAVING Quantity > 0
I apologize for not being able to provide sample data/columns. I am not allowed to share my work data.
The logic which I have been told to implement is as follows.
For each unique pair combination of col1, col2, get a constructed attribute called Quantity. Quantity = col4 wherever col3 = 8. If col3 != 8, then check SUM(col5) > 0. If yes then check col4 - SUM(col5) > 0. If yes, then keep the record, else skip.
Out of my own observation I checked that COUNT(DISTINCT col4) for each unique pair of col1 and col2 is 1. I hope that's helpful answering my question.
We are working with Spark SQL so I don't know what tag to use for this in the question.
group-by
group-by
asked 4 mins ago
scientific_explorerscientific_explorer
1
New contributor
scientific_explorer is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 4 mins ago
scientific_explorerscientific_explorer
1
New contributor
scientific_explorer is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 4 mins ago
scientific_explorerscientific_explorer
1
New contributor
scientific_explorer is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 4 mins ago
scientific_explorerscientific_explorer
1
asked 4 mins ago
scientific_explorerscientific_explorer
1
1
New contributor
scientific_explorer is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
scientific_explorer is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
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