Listing indexes and constraints
I am looking at a SQL Server database for an application I have inherited. I have not looked into SQL Server for approximately 10 years, so please bear with me.
The database table I am looking at has a bigint NOT NULL
column called id
, yet, when I check for constraints, I don't see any, and the same holds true for all database tables.
Am I right in assuming that there is no primary key & no indexing (clustered or nonclustered) on these tables?
I ran the following queries and the results appear to confirm my suspicion:
//**returns 0**
select count(*) from INFORMATION_SCHEMA.TABLE_CONSTRAINTS;
//**returns no rows**
select * from sys.indexes
where object_id = (select object_id from sys.objects where name = 'NAME-OF-TABLE');
//**returns all tables in database**
SELECT name
FROM sys.tables
WHERE OBJECTPROPERTY(object_id,'IsIndexed') = 0;
sql-server index primary-key constraint
add a comment |
I am looking at a SQL Server database for an application I have inherited. I have not looked into SQL Server for approximately 10 years, so please bear with me.
The database table I am looking at has a bigint NOT NULL
column called id
, yet, when I check for constraints, I don't see any, and the same holds true for all database tables.
Am I right in assuming that there is no primary key & no indexing (clustered or nonclustered) on these tables?
I ran the following queries and the results appear to confirm my suspicion:
//**returns 0**
select count(*) from INFORMATION_SCHEMA.TABLE_CONSTRAINTS;
//**returns no rows**
select * from sys.indexes
where object_id = (select object_id from sys.objects where name = 'NAME-OF-TABLE');
//**returns all tables in database**
SELECT name
FROM sys.tables
WHERE OBJECTPROPERTY(object_id,'IsIndexed') = 0;
sql-server index primary-key constraint
add a comment |
I am looking at a SQL Server database for an application I have inherited. I have not looked into SQL Server for approximately 10 years, so please bear with me.
The database table I am looking at has a bigint NOT NULL
column called id
, yet, when I check for constraints, I don't see any, and the same holds true for all database tables.
Am I right in assuming that there is no primary key & no indexing (clustered or nonclustered) on these tables?
I ran the following queries and the results appear to confirm my suspicion:
//**returns 0**
select count(*) from INFORMATION_SCHEMA.TABLE_CONSTRAINTS;
//**returns no rows**
select * from sys.indexes
where object_id = (select object_id from sys.objects where name = 'NAME-OF-TABLE');
//**returns all tables in database**
SELECT name
FROM sys.tables
WHERE OBJECTPROPERTY(object_id,'IsIndexed') = 0;
sql-server index primary-key constraint
I am looking at a SQL Server database for an application I have inherited. I have not looked into SQL Server for approximately 10 years, so please bear with me.
The database table I am looking at has a bigint NOT NULL
column called id
, yet, when I check for constraints, I don't see any, and the same holds true for all database tables.
Am I right in assuming that there is no primary key & no indexing (clustered or nonclustered) on these tables?
I ran the following queries and the results appear to confirm my suspicion:
//**returns 0**
select count(*) from INFORMATION_SCHEMA.TABLE_CONSTRAINTS;
//**returns no rows**
select * from sys.indexes
where object_id = (select object_id from sys.objects where name = 'NAME-OF-TABLE');
//**returns all tables in database**
SELECT name
FROM sys.tables
WHERE OBJECTPROPERTY(object_id,'IsIndexed') = 0;
sql-server index primary-key constraint
sql-server index primary-key constraint
edited Apr 14 '14 at 20:51
Paul White♦
50.2k14269435
50.2k14269435
asked Apr 14 '14 at 19:11
ali haiderali haider
138115
138115
add a comment |
add a comment |
4 Answers
4
active
oldest
votes
These two queries may help you. The first will list all of the tables and indexes on those tables in your database. If the table does not appear in the list is does not have any indexes defined on it. These queries assume SQL Server version 2005 or newer.
SELECT
IndexName = QUOTENAME(I.name),
TableName =
QUOTENAME(SCHEMA_NAME(T.[schema_id])) +
N'.' + QUOTENAME(T.name),
IsPrimaryKey = I.is_primary_key
FROM sys.indexes AS I
INNER JOIN sys.tables AS T
ON I.[object_id] = T.[object_id]
WHERE
I.type_desc <> N'HEAP'
ORDER BY
TableName ASC,
IndexName ASC;
The second query will report for each table the identity column, if any on each table in your database.
SELECT
TableName =
QUOTENAME(SCHEMA_NAME(T.[schema_id])) +
N'.' + QUOTENAME(T.name),
IdentityColumn = COALESCE(QUOTENAME(C.name), N'No identity column')
FROM sys.tables AS T
LEFT OUTER JOIN sys.columns AS C
ON T.[object_id] = C.[object_id]
AND C.is_identity = 1
ORDER BY
TableName ASC;
To limit the queries to a specific table add a WHERE
clause similar to:
WHERE T.name = N'NAME-OF-TABLE'
add a comment |
No, something is incorrect.
The check on sys.indexes
should return a row even if your table has no indexes. The heap still has a record in sys.indexes
with a type_desc
of 'HEAP' and type
of 0.
I think you probably need to make sure you are in the right database context since OBJECT_ID()
and sys.objects
are database-specific.
Try this:
USE MyDatabase
SELECT *
FROM sys.indexes
WHERE object_id = OBJECT_ID('schema.MyTableName')
add a comment |
I am not sure if you're interested in all constraints but INFORMATION_SCHEMA.TABLE_CONSTRAINTS doesn't seem to return the DEFAULT constraints -- TABLE_CONSTRAINTS (Transact-SQL)
CHECK, UNIQUE, PRIMARY KEY, FOREIGN KEY
This query will do a simple count against the sys.objects DMV:
select COUNT(*)
from sys.objects o
where o.type_desc like '%CONSTRAINT%';
If you are interested in listing the tables, you could run something like this:
select distinct
o.object_id
, QUOTENAME(s.name) + '.' + QUOTENAME(o.name) as [object_name]
, o.type_desc
, case when dc.parent_object_id is null then 'No' else 'Yes' end as has_default_constraint
, case when cc.parent_object_id is null then 'No' else 'Yes' end as has_check_constraint
, case when fk.parent_object_id is null then 'No' else 'Yes' end as has_foreing_key
, case when kc.parent_object_id is null then 'No' else 'Yes' end as has_primary_key
from sys.objects o
inner join sys.schemas s on s.schema_id = o.schema_id
left outer join sys.default_constraints dc on dc.parent_object_id = o.object_id and dc.schema_id = o.schema_id
left outer join sys.check_constraints cc on cc.parent_object_id = o.object_id and cc.schema_id = o.schema_id
left outer join sys.foreign_keys fk on fk.parent_object_id = o.object_id and fk.schema_id = o.schema_id
left outer join sys.key_constraints kc on kc.parent_object_id = o.object_id and kc.schema_id = o.schema_id
where o.is_ms_shipped = 0
and o.type = 'U'
order by [object_name];
This one should give you the info on your indexes:
select o.name
, i.*
from sys.objects o
inner join sys.indexes i on i.object_id = o.object_id
where o.is_ms_shipped = 0
and i.object_id > 100
and i.index_id > 0
order by o.name
, i.index_id;
- Index_Id = 0 -- HEAP (won't show up)
- Index_Id = 1 -- CLUSTERED
- Index_Id > 1 -- NONCLUSTERED
could you explain why you haveobject_id > 100
?
– brianc
Oct 5 '17 at 20:55
@bluevoodoo1 -- not mandatory but < 100 are the system objects but since using o.is_ms_shipped = 0, should not include them anyway. Just playing safe, that's all
– DenisT
Nov 1 '17 at 11:53
add a comment |
Well Explained Above Article
Keep Posting such Good Things
https://www.zonalstudy.com/download-electrical-power-by-w-j-r-h-pooler-pdf/
New contributor
add a comment |
Your Answer
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "182"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: false,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: null,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fdba.stackexchange.com%2fquestions%2f63185%2flisting-indexes-and-constraints%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
4 Answers
4
active
oldest
votes
4 Answers
4
active
oldest
votes
active
oldest
votes
active
oldest
votes
These two queries may help you. The first will list all of the tables and indexes on those tables in your database. If the table does not appear in the list is does not have any indexes defined on it. These queries assume SQL Server version 2005 or newer.
SELECT
IndexName = QUOTENAME(I.name),
TableName =
QUOTENAME(SCHEMA_NAME(T.[schema_id])) +
N'.' + QUOTENAME(T.name),
IsPrimaryKey = I.is_primary_key
FROM sys.indexes AS I
INNER JOIN sys.tables AS T
ON I.[object_id] = T.[object_id]
WHERE
I.type_desc <> N'HEAP'
ORDER BY
TableName ASC,
IndexName ASC;
The second query will report for each table the identity column, if any on each table in your database.
SELECT
TableName =
QUOTENAME(SCHEMA_NAME(T.[schema_id])) +
N'.' + QUOTENAME(T.name),
IdentityColumn = COALESCE(QUOTENAME(C.name), N'No identity column')
FROM sys.tables AS T
LEFT OUTER JOIN sys.columns AS C
ON T.[object_id] = C.[object_id]
AND C.is_identity = 1
ORDER BY
TableName ASC;
To limit the queries to a specific table add a WHERE
clause similar to:
WHERE T.name = N'NAME-OF-TABLE'
add a comment |
These two queries may help you. The first will list all of the tables and indexes on those tables in your database. If the table does not appear in the list is does not have any indexes defined on it. These queries assume SQL Server version 2005 or newer.
SELECT
IndexName = QUOTENAME(I.name),
TableName =
QUOTENAME(SCHEMA_NAME(T.[schema_id])) +
N'.' + QUOTENAME(T.name),
IsPrimaryKey = I.is_primary_key
FROM sys.indexes AS I
INNER JOIN sys.tables AS T
ON I.[object_id] = T.[object_id]
WHERE
I.type_desc <> N'HEAP'
ORDER BY
TableName ASC,
IndexName ASC;
The second query will report for each table the identity column, if any on each table in your database.
SELECT
TableName =
QUOTENAME(SCHEMA_NAME(T.[schema_id])) +
N'.' + QUOTENAME(T.name),
IdentityColumn = COALESCE(QUOTENAME(C.name), N'No identity column')
FROM sys.tables AS T
LEFT OUTER JOIN sys.columns AS C
ON T.[object_id] = C.[object_id]
AND C.is_identity = 1
ORDER BY
TableName ASC;
To limit the queries to a specific table add a WHERE
clause similar to:
WHERE T.name = N'NAME-OF-TABLE'
add a comment |
These two queries may help you. The first will list all of the tables and indexes on those tables in your database. If the table does not appear in the list is does not have any indexes defined on it. These queries assume SQL Server version 2005 or newer.
SELECT
IndexName = QUOTENAME(I.name),
TableName =
QUOTENAME(SCHEMA_NAME(T.[schema_id])) +
N'.' + QUOTENAME(T.name),
IsPrimaryKey = I.is_primary_key
FROM sys.indexes AS I
INNER JOIN sys.tables AS T
ON I.[object_id] = T.[object_id]
WHERE
I.type_desc <> N'HEAP'
ORDER BY
TableName ASC,
IndexName ASC;
The second query will report for each table the identity column, if any on each table in your database.
SELECT
TableName =
QUOTENAME(SCHEMA_NAME(T.[schema_id])) +
N'.' + QUOTENAME(T.name),
IdentityColumn = COALESCE(QUOTENAME(C.name), N'No identity column')
FROM sys.tables AS T
LEFT OUTER JOIN sys.columns AS C
ON T.[object_id] = C.[object_id]
AND C.is_identity = 1
ORDER BY
TableName ASC;
To limit the queries to a specific table add a WHERE
clause similar to:
WHERE T.name = N'NAME-OF-TABLE'
These two queries may help you. The first will list all of the tables and indexes on those tables in your database. If the table does not appear in the list is does not have any indexes defined on it. These queries assume SQL Server version 2005 or newer.
SELECT
IndexName = QUOTENAME(I.name),
TableName =
QUOTENAME(SCHEMA_NAME(T.[schema_id])) +
N'.' + QUOTENAME(T.name),
IsPrimaryKey = I.is_primary_key
FROM sys.indexes AS I
INNER JOIN sys.tables AS T
ON I.[object_id] = T.[object_id]
WHERE
I.type_desc <> N'HEAP'
ORDER BY
TableName ASC,
IndexName ASC;
The second query will report for each table the identity column, if any on each table in your database.
SELECT
TableName =
QUOTENAME(SCHEMA_NAME(T.[schema_id])) +
N'.' + QUOTENAME(T.name),
IdentityColumn = COALESCE(QUOTENAME(C.name), N'No identity column')
FROM sys.tables AS T
LEFT OUTER JOIN sys.columns AS C
ON T.[object_id] = C.[object_id]
AND C.is_identity = 1
ORDER BY
TableName ASC;
To limit the queries to a specific table add a WHERE
clause similar to:
WHERE T.name = N'NAME-OF-TABLE'
edited Jan 26 '16 at 13:53
Paul White♦
50.2k14269435
50.2k14269435
answered Apr 14 '14 at 20:40
JeremyJeremy
41026
41026
add a comment |
add a comment |
No, something is incorrect.
The check on sys.indexes
should return a row even if your table has no indexes. The heap still has a record in sys.indexes
with a type_desc
of 'HEAP' and type
of 0.
I think you probably need to make sure you are in the right database context since OBJECT_ID()
and sys.objects
are database-specific.
Try this:
USE MyDatabase
SELECT *
FROM sys.indexes
WHERE object_id = OBJECT_ID('schema.MyTableName')
add a comment |
No, something is incorrect.
The check on sys.indexes
should return a row even if your table has no indexes. The heap still has a record in sys.indexes
with a type_desc
of 'HEAP' and type
of 0.
I think you probably need to make sure you are in the right database context since OBJECT_ID()
and sys.objects
are database-specific.
Try this:
USE MyDatabase
SELECT *
FROM sys.indexes
WHERE object_id = OBJECT_ID('schema.MyTableName')
add a comment |
No, something is incorrect.
The check on sys.indexes
should return a row even if your table has no indexes. The heap still has a record in sys.indexes
with a type_desc
of 'HEAP' and type
of 0.
I think you probably need to make sure you are in the right database context since OBJECT_ID()
and sys.objects
are database-specific.
Try this:
USE MyDatabase
SELECT *
FROM sys.indexes
WHERE object_id = OBJECT_ID('schema.MyTableName')
No, something is incorrect.
The check on sys.indexes
should return a row even if your table has no indexes. The heap still has a record in sys.indexes
with a type_desc
of 'HEAP' and type
of 0.
I think you probably need to make sure you are in the right database context since OBJECT_ID()
and sys.objects
are database-specific.
Try this:
USE MyDatabase
SELECT *
FROM sys.indexes
WHERE object_id = OBJECT_ID('schema.MyTableName')
answered Apr 14 '14 at 19:46
JNKJNK
15.7k55091
15.7k55091
add a comment |
add a comment |
I am not sure if you're interested in all constraints but INFORMATION_SCHEMA.TABLE_CONSTRAINTS doesn't seem to return the DEFAULT constraints -- TABLE_CONSTRAINTS (Transact-SQL)
CHECK, UNIQUE, PRIMARY KEY, FOREIGN KEY
This query will do a simple count against the sys.objects DMV:
select COUNT(*)
from sys.objects o
where o.type_desc like '%CONSTRAINT%';
If you are interested in listing the tables, you could run something like this:
select distinct
o.object_id
, QUOTENAME(s.name) + '.' + QUOTENAME(o.name) as [object_name]
, o.type_desc
, case when dc.parent_object_id is null then 'No' else 'Yes' end as has_default_constraint
, case when cc.parent_object_id is null then 'No' else 'Yes' end as has_check_constraint
, case when fk.parent_object_id is null then 'No' else 'Yes' end as has_foreing_key
, case when kc.parent_object_id is null then 'No' else 'Yes' end as has_primary_key
from sys.objects o
inner join sys.schemas s on s.schema_id = o.schema_id
left outer join sys.default_constraints dc on dc.parent_object_id = o.object_id and dc.schema_id = o.schema_id
left outer join sys.check_constraints cc on cc.parent_object_id = o.object_id and cc.schema_id = o.schema_id
left outer join sys.foreign_keys fk on fk.parent_object_id = o.object_id and fk.schema_id = o.schema_id
left outer join sys.key_constraints kc on kc.parent_object_id = o.object_id and kc.schema_id = o.schema_id
where o.is_ms_shipped = 0
and o.type = 'U'
order by [object_name];
This one should give you the info on your indexes:
select o.name
, i.*
from sys.objects o
inner join sys.indexes i on i.object_id = o.object_id
where o.is_ms_shipped = 0
and i.object_id > 100
and i.index_id > 0
order by o.name
, i.index_id;
- Index_Id = 0 -- HEAP (won't show up)
- Index_Id = 1 -- CLUSTERED
- Index_Id > 1 -- NONCLUSTERED
could you explain why you haveobject_id > 100
?
– brianc
Oct 5 '17 at 20:55
@bluevoodoo1 -- not mandatory but < 100 are the system objects but since using o.is_ms_shipped = 0, should not include them anyway. Just playing safe, that's all
– DenisT
Nov 1 '17 at 11:53
add a comment |
I am not sure if you're interested in all constraints but INFORMATION_SCHEMA.TABLE_CONSTRAINTS doesn't seem to return the DEFAULT constraints -- TABLE_CONSTRAINTS (Transact-SQL)
CHECK, UNIQUE, PRIMARY KEY, FOREIGN KEY
This query will do a simple count against the sys.objects DMV:
select COUNT(*)
from sys.objects o
where o.type_desc like '%CONSTRAINT%';
If you are interested in listing the tables, you could run something like this:
select distinct
o.object_id
, QUOTENAME(s.name) + '.' + QUOTENAME(o.name) as [object_name]
, o.type_desc
, case when dc.parent_object_id is null then 'No' else 'Yes' end as has_default_constraint
, case when cc.parent_object_id is null then 'No' else 'Yes' end as has_check_constraint
, case when fk.parent_object_id is null then 'No' else 'Yes' end as has_foreing_key
, case when kc.parent_object_id is null then 'No' else 'Yes' end as has_primary_key
from sys.objects o
inner join sys.schemas s on s.schema_id = o.schema_id
left outer join sys.default_constraints dc on dc.parent_object_id = o.object_id and dc.schema_id = o.schema_id
left outer join sys.check_constraints cc on cc.parent_object_id = o.object_id and cc.schema_id = o.schema_id
left outer join sys.foreign_keys fk on fk.parent_object_id = o.object_id and fk.schema_id = o.schema_id
left outer join sys.key_constraints kc on kc.parent_object_id = o.object_id and kc.schema_id = o.schema_id
where o.is_ms_shipped = 0
and o.type = 'U'
order by [object_name];
This one should give you the info on your indexes:
select o.name
, i.*
from sys.objects o
inner join sys.indexes i on i.object_id = o.object_id
where o.is_ms_shipped = 0
and i.object_id > 100
and i.index_id > 0
order by o.name
, i.index_id;
- Index_Id = 0 -- HEAP (won't show up)
- Index_Id = 1 -- CLUSTERED
- Index_Id > 1 -- NONCLUSTERED
could you explain why you haveobject_id > 100
?
– brianc
Oct 5 '17 at 20:55
@bluevoodoo1 -- not mandatory but < 100 are the system objects but since using o.is_ms_shipped = 0, should not include them anyway. Just playing safe, that's all
– DenisT
Nov 1 '17 at 11:53
add a comment |
I am not sure if you're interested in all constraints but INFORMATION_SCHEMA.TABLE_CONSTRAINTS doesn't seem to return the DEFAULT constraints -- TABLE_CONSTRAINTS (Transact-SQL)
CHECK, UNIQUE, PRIMARY KEY, FOREIGN KEY
This query will do a simple count against the sys.objects DMV:
select COUNT(*)
from sys.objects o
where o.type_desc like '%CONSTRAINT%';
If you are interested in listing the tables, you could run something like this:
select distinct
o.object_id
, QUOTENAME(s.name) + '.' + QUOTENAME(o.name) as [object_name]
, o.type_desc
, case when dc.parent_object_id is null then 'No' else 'Yes' end as has_default_constraint
, case when cc.parent_object_id is null then 'No' else 'Yes' end as has_check_constraint
, case when fk.parent_object_id is null then 'No' else 'Yes' end as has_foreing_key
, case when kc.parent_object_id is null then 'No' else 'Yes' end as has_primary_key
from sys.objects o
inner join sys.schemas s on s.schema_id = o.schema_id
left outer join sys.default_constraints dc on dc.parent_object_id = o.object_id and dc.schema_id = o.schema_id
left outer join sys.check_constraints cc on cc.parent_object_id = o.object_id and cc.schema_id = o.schema_id
left outer join sys.foreign_keys fk on fk.parent_object_id = o.object_id and fk.schema_id = o.schema_id
left outer join sys.key_constraints kc on kc.parent_object_id = o.object_id and kc.schema_id = o.schema_id
where o.is_ms_shipped = 0
and o.type = 'U'
order by [object_name];
This one should give you the info on your indexes:
select o.name
, i.*
from sys.objects o
inner join sys.indexes i on i.object_id = o.object_id
where o.is_ms_shipped = 0
and i.object_id > 100
and i.index_id > 0
order by o.name
, i.index_id;
- Index_Id = 0 -- HEAP (won't show up)
- Index_Id = 1 -- CLUSTERED
- Index_Id > 1 -- NONCLUSTERED
I am not sure if you're interested in all constraints but INFORMATION_SCHEMA.TABLE_CONSTRAINTS doesn't seem to return the DEFAULT constraints -- TABLE_CONSTRAINTS (Transact-SQL)
CHECK, UNIQUE, PRIMARY KEY, FOREIGN KEY
This query will do a simple count against the sys.objects DMV:
select COUNT(*)
from sys.objects o
where o.type_desc like '%CONSTRAINT%';
If you are interested in listing the tables, you could run something like this:
select distinct
o.object_id
, QUOTENAME(s.name) + '.' + QUOTENAME(o.name) as [object_name]
, o.type_desc
, case when dc.parent_object_id is null then 'No' else 'Yes' end as has_default_constraint
, case when cc.parent_object_id is null then 'No' else 'Yes' end as has_check_constraint
, case when fk.parent_object_id is null then 'No' else 'Yes' end as has_foreing_key
, case when kc.parent_object_id is null then 'No' else 'Yes' end as has_primary_key
from sys.objects o
inner join sys.schemas s on s.schema_id = o.schema_id
left outer join sys.default_constraints dc on dc.parent_object_id = o.object_id and dc.schema_id = o.schema_id
left outer join sys.check_constraints cc on cc.parent_object_id = o.object_id and cc.schema_id = o.schema_id
left outer join sys.foreign_keys fk on fk.parent_object_id = o.object_id and fk.schema_id = o.schema_id
left outer join sys.key_constraints kc on kc.parent_object_id = o.object_id and kc.schema_id = o.schema_id
where o.is_ms_shipped = 0
and o.type = 'U'
order by [object_name];
This one should give you the info on your indexes:
select o.name
, i.*
from sys.objects o
inner join sys.indexes i on i.object_id = o.object_id
where o.is_ms_shipped = 0
and i.object_id > 100
and i.index_id > 0
order by o.name
, i.index_id;
- Index_Id = 0 -- HEAP (won't show up)
- Index_Id = 1 -- CLUSTERED
- Index_Id > 1 -- NONCLUSTERED
answered Apr 14 '14 at 20:20
DenisTDenisT
580136
580136
could you explain why you haveobject_id > 100
?
– brianc
Oct 5 '17 at 20:55
@bluevoodoo1 -- not mandatory but < 100 are the system objects but since using o.is_ms_shipped = 0, should not include them anyway. Just playing safe, that's all
– DenisT
Nov 1 '17 at 11:53
add a comment |
could you explain why you haveobject_id > 100
?
– brianc
Oct 5 '17 at 20:55
@bluevoodoo1 -- not mandatory but < 100 are the system objects but since using o.is_ms_shipped = 0, should not include them anyway. Just playing safe, that's all
– DenisT
Nov 1 '17 at 11:53
could you explain why you have
object_id > 100
?– brianc
Oct 5 '17 at 20:55
could you explain why you have
object_id > 100
?– brianc
Oct 5 '17 at 20:55
@bluevoodoo1 -- not mandatory but < 100 are the system objects but since using o.is_ms_shipped = 0, should not include them anyway. Just playing safe, that's all
– DenisT
Nov 1 '17 at 11:53
@bluevoodoo1 -- not mandatory but < 100 are the system objects but since using o.is_ms_shipped = 0, should not include them anyway. Just playing safe, that's all
– DenisT
Nov 1 '17 at 11:53
add a comment |
Well Explained Above Article
Keep Posting such Good Things
https://www.zonalstudy.com/download-electrical-power-by-w-j-r-h-pooler-pdf/
New contributor
add a comment |
Well Explained Above Article
Keep Posting such Good Things
https://www.zonalstudy.com/download-electrical-power-by-w-j-r-h-pooler-pdf/
New contributor
add a comment |
Well Explained Above Article
Keep Posting such Good Things
https://www.zonalstudy.com/download-electrical-power-by-w-j-r-h-pooler-pdf/
New contributor
Well Explained Above Article
Keep Posting such Good Things
https://www.zonalstudy.com/download-electrical-power-by-w-j-r-h-pooler-pdf/
New contributor
New contributor
answered 6 mins ago
RajRaj
1
1
New contributor
New contributor
add a comment |
add a comment |
Thanks for contributing an answer to Database Administrators Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fdba.stackexchange.com%2fquestions%2f63185%2flisting-indexes-and-constraints%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown