MySQL get previous row with inner join












0















In my query, I need to get the previous row with the current row and everything works fine here.



SELECT *,
(SELECT calendar_id
FROM calendar AS sub
WHERE sub.calendar_id < calendar.calendar_id
ORDER BY sub.calendar_id DESC
LIMIT 1) AS previous
FROM calendar


But now i need to join more two tables i using inner join for what.



SELECT *,
(SELECT calendar_id
FROM calendar AS sub
WHERE sub.calendar_id < calendar.calendar_id
ORDER BY sub.calendar_id DESC
LIMIT 1) AS previous
FROM calendar
INNER JOIN relationships
ON calendar.relation_id = relationships.relation_id
INNER JOIN customers
ON customers.customer_id = relationships.customer_id
WHERE relationships.user_id = '$user_id'
AND Date_format(calendar.date, '%m-%Y') = '$date'
ORDER BY calendar.date ASC


Here is my final query with inner joins, but that part about previous row now result is just mixed. How i can keep my previous row result good and have that data from other tables with inner join?










share|improve this question














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  • What does "mixed" mean? Don't you get the results you want?

    – ypercubeᵀᴹ
    Apr 18 '18 at 17:36











  • If the problem is that sometimes the previous row isn't included in the result set, then you need to perform the joins with the previous sub-query, as well as in the main query.

    – RDFozz
    Apr 18 '18 at 17:48
















0















In my query, I need to get the previous row with the current row and everything works fine here.



SELECT *,
(SELECT calendar_id
FROM calendar AS sub
WHERE sub.calendar_id < calendar.calendar_id
ORDER BY sub.calendar_id DESC
LIMIT 1) AS previous
FROM calendar


But now i need to join more two tables i using inner join for what.



SELECT *,
(SELECT calendar_id
FROM calendar AS sub
WHERE sub.calendar_id < calendar.calendar_id
ORDER BY sub.calendar_id DESC
LIMIT 1) AS previous
FROM calendar
INNER JOIN relationships
ON calendar.relation_id = relationships.relation_id
INNER JOIN customers
ON customers.customer_id = relationships.customer_id
WHERE relationships.user_id = '$user_id'
AND Date_format(calendar.date, '%m-%Y') = '$date'
ORDER BY calendar.date ASC


Here is my final query with inner joins, but that part about previous row now result is just mixed. How i can keep my previous row result good and have that data from other tables with inner join?










share|improve this question














bumped to the homepage by Community 8 mins ago


This question has answers that may be good or bad; the system has marked it active so that they can be reviewed.
















  • What does "mixed" mean? Don't you get the results you want?

    – ypercubeᵀᴹ
    Apr 18 '18 at 17:36











  • If the problem is that sometimes the previous row isn't included in the result set, then you need to perform the joins with the previous sub-query, as well as in the main query.

    – RDFozz
    Apr 18 '18 at 17:48














0












0








0








In my query, I need to get the previous row with the current row and everything works fine here.



SELECT *,
(SELECT calendar_id
FROM calendar AS sub
WHERE sub.calendar_id < calendar.calendar_id
ORDER BY sub.calendar_id DESC
LIMIT 1) AS previous
FROM calendar


But now i need to join more two tables i using inner join for what.



SELECT *,
(SELECT calendar_id
FROM calendar AS sub
WHERE sub.calendar_id < calendar.calendar_id
ORDER BY sub.calendar_id DESC
LIMIT 1) AS previous
FROM calendar
INNER JOIN relationships
ON calendar.relation_id = relationships.relation_id
INNER JOIN customers
ON customers.customer_id = relationships.customer_id
WHERE relationships.user_id = '$user_id'
AND Date_format(calendar.date, '%m-%Y') = '$date'
ORDER BY calendar.date ASC


Here is my final query with inner joins, but that part about previous row now result is just mixed. How i can keep my previous row result good and have that data from other tables with inner join?










share|improve this question














In my query, I need to get the previous row with the current row and everything works fine here.



SELECT *,
(SELECT calendar_id
FROM calendar AS sub
WHERE sub.calendar_id < calendar.calendar_id
ORDER BY sub.calendar_id DESC
LIMIT 1) AS previous
FROM calendar


But now i need to join more two tables i using inner join for what.



SELECT *,
(SELECT calendar_id
FROM calendar AS sub
WHERE sub.calendar_id < calendar.calendar_id
ORDER BY sub.calendar_id DESC
LIMIT 1) AS previous
FROM calendar
INNER JOIN relationships
ON calendar.relation_id = relationships.relation_id
INNER JOIN customers
ON customers.customer_id = relationships.customer_id
WHERE relationships.user_id = '$user_id'
AND Date_format(calendar.date, '%m-%Y') = '$date'
ORDER BY calendar.date ASC


Here is my final query with inner joins, but that part about previous row now result is just mixed. How i can keep my previous row result good and have that data from other tables with inner join?







mysql join






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asked Apr 18 '18 at 17:19









SkySonnySkySonny

1




1





bumped to the homepage by Community 8 mins ago


This question has answers that may be good or bad; the system has marked it active so that they can be reviewed.







bumped to the homepage by Community 8 mins ago


This question has answers that may be good or bad; the system has marked it active so that they can be reviewed.















  • What does "mixed" mean? Don't you get the results you want?

    – ypercubeᵀᴹ
    Apr 18 '18 at 17:36











  • If the problem is that sometimes the previous row isn't included in the result set, then you need to perform the joins with the previous sub-query, as well as in the main query.

    – RDFozz
    Apr 18 '18 at 17:48



















  • What does "mixed" mean? Don't you get the results you want?

    – ypercubeᵀᴹ
    Apr 18 '18 at 17:36











  • If the problem is that sometimes the previous row isn't included in the result set, then you need to perform the joins with the previous sub-query, as well as in the main query.

    – RDFozz
    Apr 18 '18 at 17:48

















What does "mixed" mean? Don't you get the results you want?

– ypercubeᵀᴹ
Apr 18 '18 at 17:36





What does "mixed" mean? Don't you get the results you want?

– ypercubeᵀᴹ
Apr 18 '18 at 17:36













If the problem is that sometimes the previous row isn't included in the result set, then you need to perform the joins with the previous sub-query, as well as in the main query.

– RDFozz
Apr 18 '18 at 17:48





If the problem is that sometimes the previous row isn't included in the result set, then you need to perform the joins with the previous sub-query, as well as in the main query.

– RDFozz
Apr 18 '18 at 17:48










1 Answer
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Use that query as a 'derived table' to finish the task:



SELECT ...
FROM ( ... your query ... ) AS x
JOIN calendar AS prev_row ON prev_row.calendar_id = x.previous
...


(If you are using MySQL 8.0, there is a "windowing" way to get the previous id.)






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    0














    Use that query as a 'derived table' to finish the task:



    SELECT ...
    FROM ( ... your query ... ) AS x
    JOIN calendar AS prev_row ON prev_row.calendar_id = x.previous
    ...


    (If you are using MySQL 8.0, there is a "windowing" way to get the previous id.)






    share|improve this answer




























      0














      Use that query as a 'derived table' to finish the task:



      SELECT ...
      FROM ( ... your query ... ) AS x
      JOIN calendar AS prev_row ON prev_row.calendar_id = x.previous
      ...


      (If you are using MySQL 8.0, there is a "windowing" way to get the previous id.)






      share|improve this answer


























        0












        0








        0







        Use that query as a 'derived table' to finish the task:



        SELECT ...
        FROM ( ... your query ... ) AS x
        JOIN calendar AS prev_row ON prev_row.calendar_id = x.previous
        ...


        (If you are using MySQL 8.0, there is a "windowing" way to get the previous id.)






        share|improve this answer













        Use that query as a 'derived table' to finish the task:



        SELECT ...
        FROM ( ... your query ... ) AS x
        JOIN calendar AS prev_row ON prev_row.calendar_id = x.previous
        ...


        (If you are using MySQL 8.0, there is a "windowing" way to get the previous id.)







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered May 5 '18 at 14:54









        Rick JamesRick James

        42k22258




        42k22258






























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