Select the value of max(date) and id with mysql
I want the last dated record. But my query doesn't work. Where am I doing wrong?
Example data:
|-------------------------------------------------------------------|
| id | messagges | mes_date | send_user | rec_user |
|-------------------------------------------------------------------|
| 1 | hello | 2019-01-18 12:12:12 | 7 | 1 |
| 2 | forget | 2019-01-16 10:10:10 | 8 | 3 |
| 3 | say | 2019-02-20 14:14:14 | 9 | 1 |
| 4 | drink | 2018-12-16 08:08:08 | 10 | 3 |
|-------------------------------------------------------------------|
My query:
SELECT distinct lst.id,lst.messagges,lst.mes_date, lst.rec_user
FROM mes_table lst
join (select mes_date, id from messagges
order by mes_date desc) as msg on lst.id = msg.id
group by lst.rec_user
I need:
|--------------------------------------------------------|
| id | messagges | mes_date | rec_user |
|--------------------------------------------------------|
| 2 | forget | 2019-01-16 10:10:10 | 3 |
| 3 | say | 2019-02-20 14:14:14 | 1 |
|--------------------------------------------------------|
mysql query
New contributor
Tota1907 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
I want the last dated record. But my query doesn't work. Where am I doing wrong?
Example data:
|-------------------------------------------------------------------|
| id | messagges | mes_date | send_user | rec_user |
|-------------------------------------------------------------------|
| 1 | hello | 2019-01-18 12:12:12 | 7 | 1 |
| 2 | forget | 2019-01-16 10:10:10 | 8 | 3 |
| 3 | say | 2019-02-20 14:14:14 | 9 | 1 |
| 4 | drink | 2018-12-16 08:08:08 | 10 | 3 |
|-------------------------------------------------------------------|
My query:
SELECT distinct lst.id,lst.messagges,lst.mes_date, lst.rec_user
FROM mes_table lst
join (select mes_date, id from messagges
order by mes_date desc) as msg on lst.id = msg.id
group by lst.rec_user
I need:
|--------------------------------------------------------|
| id | messagges | mes_date | rec_user |
|--------------------------------------------------------|
| 2 | forget | 2019-01-16 10:10:10 | 3 |
| 3 | say | 2019-02-20 14:14:14 | 1 |
|--------------------------------------------------------|
mysql query
New contributor
Tota1907 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
I want the last dated record. But my query doesn't work. Where am I doing wrong?
Example data:
|-------------------------------------------------------------------|
| id | messagges | mes_date | send_user | rec_user |
|-------------------------------------------------------------------|
| 1 | hello | 2019-01-18 12:12:12 | 7 | 1 |
| 2 | forget | 2019-01-16 10:10:10 | 8 | 3 |
| 3 | say | 2019-02-20 14:14:14 | 9 | 1 |
| 4 | drink | 2018-12-16 08:08:08 | 10 | 3 |
|-------------------------------------------------------------------|
My query:
SELECT distinct lst.id,lst.messagges,lst.mes_date, lst.rec_user
FROM mes_table lst
join (select mes_date, id from messagges
order by mes_date desc) as msg on lst.id = msg.id
group by lst.rec_user
I need:
|--------------------------------------------------------|
| id | messagges | mes_date | rec_user |
|--------------------------------------------------------|
| 2 | forget | 2019-01-16 10:10:10 | 3 |
| 3 | say | 2019-02-20 14:14:14 | 1 |
|--------------------------------------------------------|
mysql query
New contributor
Tota1907 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
I want the last dated record. But my query doesn't work. Where am I doing wrong?
Example data:
|-------------------------------------------------------------------|
| id | messagges | mes_date | send_user | rec_user |
|-------------------------------------------------------------------|
| 1 | hello | 2019-01-18 12:12:12 | 7 | 1 |
| 2 | forget | 2019-01-16 10:10:10 | 8 | 3 |
| 3 | say | 2019-02-20 14:14:14 | 9 | 1 |
| 4 | drink | 2018-12-16 08:08:08 | 10 | 3 |
|-------------------------------------------------------------------|
My query:
SELECT distinct lst.id,lst.messagges,lst.mes_date, lst.rec_user
FROM mes_table lst
join (select mes_date, id from messagges
order by mes_date desc) as msg on lst.id = msg.id
group by lst.rec_user
I need:
|--------------------------------------------------------|
| id | messagges | mes_date | rec_user |
|--------------------------------------------------------|
| 2 | forget | 2019-01-16 10:10:10 | 3 |
| 3 | say | 2019-02-20 14:14:14 | 1 |
|--------------------------------------------------------|
mysql query
mysql query
New contributor
Tota1907 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Tota1907 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Tota1907 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 12 hours ago
Tota1907Tota1907
1
1
New contributor
Tota1907 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Tota1907 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Tota1907 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
- Don't mix
DISTINCTandGROUP BY. The do roughly the same thing. - When you want just the last, use
ORDER BY .. DESC LIMIT 1
Simplify to
SELECT lst.id, lst.messagges, lst.mes_date, lst.rec_user
FROM mes_table AS lst
JOIN messagges AS msg ON msg.id = lst.id
ORDER BY msg.mes_date DESC
LIMIT 1
add a comment |
Your Answer
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "182"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: false,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: null,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Tota1907 is a new contributor. Be nice, and check out our Code of Conduct.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fdba.stackexchange.com%2fquestions%2f227529%2fselect-the-value-of-maxdate-and-id-with-mysql%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
- Don't mix
DISTINCTandGROUP BY. The do roughly the same thing. - When you want just the last, use
ORDER BY .. DESC LIMIT 1
Simplify to
SELECT lst.id, lst.messagges, lst.mes_date, lst.rec_user
FROM mes_table AS lst
JOIN messagges AS msg ON msg.id = lst.id
ORDER BY msg.mes_date DESC
LIMIT 1
add a comment |
- Don't mix
DISTINCTandGROUP BY. The do roughly the same thing. - When you want just the last, use
ORDER BY .. DESC LIMIT 1
Simplify to
SELECT lst.id, lst.messagges, lst.mes_date, lst.rec_user
FROM mes_table AS lst
JOIN messagges AS msg ON msg.id = lst.id
ORDER BY msg.mes_date DESC
LIMIT 1
add a comment |
- Don't mix
DISTINCTandGROUP BY. The do roughly the same thing. - When you want just the last, use
ORDER BY .. DESC LIMIT 1
Simplify to
SELECT lst.id, lst.messagges, lst.mes_date, lst.rec_user
FROM mes_table AS lst
JOIN messagges AS msg ON msg.id = lst.id
ORDER BY msg.mes_date DESC
LIMIT 1
- Don't mix
DISTINCTandGROUP BY. The do roughly the same thing. - When you want just the last, use
ORDER BY .. DESC LIMIT 1
Simplify to
SELECT lst.id, lst.messagges, lst.mes_date, lst.rec_user
FROM mes_table AS lst
JOIN messagges AS msg ON msg.id = lst.id
ORDER BY msg.mes_date DESC
LIMIT 1
answered 12 hours ago
Rick JamesRick James
41.5k22258
41.5k22258
add a comment |
add a comment |
Tota1907 is a new contributor. Be nice, and check out our Code of Conduct.
Tota1907 is a new contributor. Be nice, and check out our Code of Conduct.
Tota1907 is a new contributor. Be nice, and check out our Code of Conduct.
Tota1907 is a new contributor. Be nice, and check out our Code of Conduct.
Thanks for contributing an answer to Database Administrators Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fdba.stackexchange.com%2fquestions%2f227529%2fselect-the-value-of-maxdate-and-id-with-mysql%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown