Mysql query to fetch records which are not matched form both tables
I am new to here.
I have two two tables , one is temporary table and another one is main table.Before doing final process user click on refresh button . Then I am populating data into the temporary table and need to display to user if there is any difference between two tables like old value - new value. For this I tried below query but not able get the old value. I am getting as null
Temporay table
+------+--------------+----------------+-----+
| asn | ean | belegnr |quantity|
+------+--------------+----------------+-----+
| 700000845 | 4046228201122| 30059314 |2 |
| 700000845 | 4046228138879| 30059314 |3 |
| 700000845 | 4046228138875| 30059320 |25 |
+------+--------------+----------------+--+--+
Main Table
+------+--------------+----------------+-----+
| asn | ean | belegnr |quantity|
+------+--------------+----------------+-----+
| 700000845 | 4046228201122| 30059314 |5 |
| 700000845 | 4046228138879| 30059314 |3 |
| 700000845 | 4046228138888| 30059320 |25 |
+------+--------------+----------------+--+--+
From both tables I have change in ean field and in quantity field
For this I am using this query
SELECT
t2.id,t2.ean,t2.belegnr,t2.`quantity`,t1.`quantity` FROM
temp_table t2
LEFT OUTER JOIN details t1 ON
t1.asn = t2.asn
AND t1.ean = t2.ean
AND t1.belegnr = t2.belegnr
AND t1.quantity = t2.quantity
WHERE t2.asn = 700000845
AND t2.`belegnr` in(30059314,30059320)
AND t1.id IS NULL
Below is the my expected result
+------+--------------+----------------+-----+----------------------
| asn | ean | oldean| belegnr |quantity|Oldqty|
+------+--------------+----------------+-----+----------------------|
| 700000845 | 4046228201122| 4046228201122 |30059314 |2 | 5 |
| 700000845 | 4046228138875| 4046228138888 |30059320 |25 | 25 |
+------+--------------+----------------+--+--+--------+-------------+
Any help would be greatly appreciated.
mysql join
asked 1 min ago
user3408779user3408779
101
New contributor
user3408779 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
I am new to here.
I have two two tables , one is temporary table and another one is main table.Before doing final process user click on refresh button . Then I am populating data into the temporary table and need to display to user if there is any difference between two tables like old value - new value. For this I tried below query but not able get the old value. I am getting as null
Temporay table
+------+--------------+----------------+-----+
| asn | ean | belegnr |quantity|
+------+--------------+----------------+-----+
| 700000845 | 4046228201122| 30059314 |2 |
| 700000845 | 4046228138879| 30059314 |3 |
| 700000845 | 4046228138875| 30059320 |25 |
+------+--------------+----------------+--+--+
Main Table
+------+--------------+----------------+-----+
| asn | ean | belegnr |quantity|
+------+--------------+----------------+-----+
| 700000845 | 4046228201122| 30059314 |5 |
| 700000845 | 4046228138879| 30059314 |3 |
| 700000845 | 4046228138888| 30059320 |25 |
+------+--------------+----------------+--+--+
From both tables I have change in ean field and in quantity field
For this I am using this query
SELECT
t2.id,t2.ean,t2.belegnr,t2.`quantity`,t1.`quantity` FROM
temp_table t2
LEFT OUTER JOIN details t1 ON
t1.asn = t2.asn
AND t1.ean = t2.ean
AND t1.belegnr = t2.belegnr
AND t1.quantity = t2.quantity
WHERE t2.asn = 700000845
AND t2.`belegnr` in(30059314,30059320)
AND t1.id IS NULL
Below is the my expected result
+------+--------------+----------------+-----+----------------------
| asn | ean | oldean| belegnr |quantity|Oldqty|
+------+--------------+----------------+-----+----------------------|
| 700000845 | 4046228201122| 4046228201122 |30059314 |2 | 5 |
| 700000845 | 4046228138875| 4046228138888 |30059320 |25 | 25 |
+------+--------------+----------------+--+--+--------+-------------+
Any help would be greatly appreciated.
mysql join
asked 1 min ago
user3408779user3408779
101
New contributor
user3408779 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
I am new to here.
I have two two tables , one is temporary table and another one is main table.Before doing final process user click on refresh button . Then I am populating data into the temporary table and need to display to user if there is any difference between two tables like old value - new value. For this I tried below query but not able get the old value. I am getting as null
Temporay table
+------+--------------+----------------+-----+
| asn | ean | belegnr |quantity|
+------+--------------+----------------+-----+
| 700000845 | 4046228201122| 30059314 |2 |
| 700000845 | 4046228138879| 30059314 |3 |
| 700000845 | 4046228138875| 30059320 |25 |
+------+--------------+----------------+--+--+
Main Table
+------+--------------+----------------+-----+
| asn | ean | belegnr |quantity|
+------+--------------+----------------+-----+
| 700000845 | 4046228201122| 30059314 |5 |
| 700000845 | 4046228138879| 30059314 |3 |
| 700000845 | 4046228138888| 30059320 |25 |
+------+--------------+----------------+--+--+
From both tables I have change in ean field and in quantity field
For this I am using this query
SELECT
t2.id,t2.ean,t2.belegnr,t2.`quantity`,t1.`quantity` FROM
temp_table t2
LEFT OUTER JOIN details t1 ON
t1.asn = t2.asn
AND t1.ean = t2.ean
AND t1.belegnr = t2.belegnr
AND t1.quantity = t2.quantity
WHERE t2.asn = 700000845
AND t2.`belegnr` in(30059314,30059320)
AND t1.id IS NULL
Below is the my expected result
+------+--------------+----------------+-----+----------------------
| asn | ean | oldean| belegnr |quantity|Oldqty|
+------+--------------+----------------+-----+----------------------|
| 700000845 | 4046228201122| 4046228201122 |30059314 |2 | 5 |
| 700000845 | 4046228138875| 4046228138888 |30059320 |25 | 25 |
+------+--------------+----------------+--+--+--------+-------------+
Any help would be greatly appreciated.
mysql join
asked 1 min ago
user3408779user3408779
101
New contributor
user3408779 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
I am new to here.
I have two two tables , one is temporary table and another one is main table.Before doing final process user click on refresh button . Then I am populating data into the temporary table and need to display to user if there is any difference between two tables like old value - new value. For this I tried below query but not able get the old value. I am getting as null
Temporay table
+------+--------------+----------------+-----+
| asn | ean | belegnr |quantity|
+------+--------------+----------------+-----+
| 700000845 | 4046228201122| 30059314 |2 |
| 700000845 | 4046228138879| 30059314 |3 |
| 700000845 | 4046228138875| 30059320 |25 |
+------+--------------+----------------+--+--+
Main Table
+------+--------------+----------------+-----+
| asn | ean | belegnr |quantity|
+------+--------------+----------------+-----+
| 700000845 | 4046228201122| 30059314 |5 |
| 700000845 | 4046228138879| 30059314 |3 |
| 700000845 | 4046228138888| 30059320 |25 |
+------+--------------+----------------+--+--+
From both tables I have change in ean field and in quantity field
For this I am using this query
SELECT
t2.id,t2.ean,t2.belegnr,t2.`quantity`,t1.`quantity` FROM
temp_table t2
LEFT OUTER JOIN details t1 ON
t1.asn = t2.asn
AND t1.ean = t2.ean
AND t1.belegnr = t2.belegnr
AND t1.quantity = t2.quantity
WHERE t2.asn = 700000845
AND t2.`belegnr` in(30059314,30059320)
AND t1.id IS NULL
Below is the my expected result
+------+--------------+----------------+-----+----------------------
| asn | ean | oldean| belegnr |quantity|Oldqty|
+------+--------------+----------------+-----+----------------------|
| 700000845 | 4046228201122| 4046228201122 |30059314 |2 | 5 |
| 700000845 | 4046228138875| 4046228138888 |30059320 |25 | 25 |
+------+--------------+----------------+--+--+--------+-------------+
Any help would be greatly appreciated.
mysql join
mysql join
asked 1 min ago
user3408779user3408779
101
New contributor
user3408779 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 1 min ago
user3408779user3408779
101
New contributor
user3408779 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 1 min ago
user3408779user3408779
101
New contributor
user3408779 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 1 min ago
user3408779user3408779
101
asked 1 min ago
user3408779user3408779
101
101
New contributor
user3408779 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
user3408779 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
user3408779 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
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