Getting aggregate sub-values in aggregate query
I have a query that need to show aggregated values in an already aggregated outer query.
Consider a query that fetches total count of accounts being credited on a certain day.
I would like to display
- total number orders
- Total orders that are "PENDING"
- Total orders that are "OPEN"
Here is the query that seems to make sense but as resultset show below, I am obviously not using the right approach. The "OPEN" column displays the entire total, the "PENDING" column stays NULL.
I feel I may be using the wrong approach, what are the options to have this work?
SELECT s.created, COUNT(s.id) 'total_accounts_credited', SUM(s.withdrawal) 'total_amount_credited',
(select count(s.id) WHERE s.status_id = 'OPEN') total_open_credited,
(select count(s.id) WHERE s.status_id = 'PENDING') total_pending_credited
FROM statements s
WHERE s.status_id in ('OPEN', 'PENDING')
GROUP BY
YEAR(s.created),
MONTH(s.created),
DAY(s.created)
ORDER BY s.created DESC
;
Results:
+---------------------+-------------------------+-----------------------+---------------------+----------------------+
| created | total_accounts_credited | total_amount_credited | total_open_credited | total_pending_credited |
+---------------------+-------------------------+-----------------------+---------------------+----------------------+
| 2019-01-19 00:00:00 | 18050 | 20813.18 | 18050 | NULL |
| 2019-01-12 00:00:00 | 18135 | 24768.43 | 18135 | NULL |
| 2019-01-10 09:00:27 | 80 | 1497.75 | 80 | NULL |
| 2019-01-09 09:20:55 | 51 | 933.50 | 51 | NULL |
| 2019-01-08 16:45:14 | 10 | 187.50 | 10 | NULL |
| 2019-01-05 18:21:00 | 17588 | 16968.49 | 17588 | NULL |
| 2018-12-29 00:00:00 | 17893 | 25404.18 | 17893 | NULL |
| 2018-12-28 15:23:04 | 1 | 35.00 | 1 | NULL |
| 2018-12-22 00:00:00 | 17353 | 17048.18 | 17353 | NULL |
| 2018-12-15 00:00:00 | 16893 | 10181.34 | 16893 | NULL |
| 2018-12-08 00:00:00 | 16220 | 99547.09 | 16220 | NULL |
| 2018-12-01 00:00:00 | 15476 | 87699.59 | 15476 | NULL |
+---------------------+-------------------------+-----------------------+---------------------+----------------------+
mysql mysql-5.6 query subquery
add a comment |
I have a query that need to show aggregated values in an already aggregated outer query.
Consider a query that fetches total count of accounts being credited on a certain day.
I would like to display
- total number orders
- Total orders that are "PENDING"
- Total orders that are "OPEN"
Here is the query that seems to make sense but as resultset show below, I am obviously not using the right approach. The "OPEN" column displays the entire total, the "PENDING" column stays NULL.
I feel I may be using the wrong approach, what are the options to have this work?
SELECT s.created, COUNT(s.id) 'total_accounts_credited', SUM(s.withdrawal) 'total_amount_credited',
(select count(s.id) WHERE s.status_id = 'OPEN') total_open_credited,
(select count(s.id) WHERE s.status_id = 'PENDING') total_pending_credited
FROM statements s
WHERE s.status_id in ('OPEN', 'PENDING')
GROUP BY
YEAR(s.created),
MONTH(s.created),
DAY(s.created)
ORDER BY s.created DESC
;
Results:
+---------------------+-------------------------+-----------------------+---------------------+----------------------+
| created | total_accounts_credited | total_amount_credited | total_open_credited | total_pending_credited |
+---------------------+-------------------------+-----------------------+---------------------+----------------------+
| 2019-01-19 00:00:00 | 18050 | 20813.18 | 18050 | NULL |
| 2019-01-12 00:00:00 | 18135 | 24768.43 | 18135 | NULL |
| 2019-01-10 09:00:27 | 80 | 1497.75 | 80 | NULL |
| 2019-01-09 09:20:55 | 51 | 933.50 | 51 | NULL |
| 2019-01-08 16:45:14 | 10 | 187.50 | 10 | NULL |
| 2019-01-05 18:21:00 | 17588 | 16968.49 | 17588 | NULL |
| 2018-12-29 00:00:00 | 17893 | 25404.18 | 17893 | NULL |
| 2018-12-28 15:23:04 | 1 | 35.00 | 1 | NULL |
| 2018-12-22 00:00:00 | 17353 | 17048.18 | 17353 | NULL |
| 2018-12-15 00:00:00 | 16893 | 10181.34 | 16893 | NULL |
| 2018-12-08 00:00:00 | 16220 | 99547.09 | 16220 | NULL |
| 2018-12-01 00:00:00 | 15476 | 87699.59 | 15476 | NULL |
+---------------------+-------------------------+-----------------------+---------------------+----------------------+
mysql mysql-5.6 query subquery
add a comment |
I have a query that need to show aggregated values in an already aggregated outer query.
Consider a query that fetches total count of accounts being credited on a certain day.
I would like to display
- total number orders
- Total orders that are "PENDING"
- Total orders that are "OPEN"
Here is the query that seems to make sense but as resultset show below, I am obviously not using the right approach. The "OPEN" column displays the entire total, the "PENDING" column stays NULL.
I feel I may be using the wrong approach, what are the options to have this work?
SELECT s.created, COUNT(s.id) 'total_accounts_credited', SUM(s.withdrawal) 'total_amount_credited',
(select count(s.id) WHERE s.status_id = 'OPEN') total_open_credited,
(select count(s.id) WHERE s.status_id = 'PENDING') total_pending_credited
FROM statements s
WHERE s.status_id in ('OPEN', 'PENDING')
GROUP BY
YEAR(s.created),
MONTH(s.created),
DAY(s.created)
ORDER BY s.created DESC
;
Results:
+---------------------+-------------------------+-----------------------+---------------------+----------------------+
| created | total_accounts_credited | total_amount_credited | total_open_credited | total_pending_credited |
+---------------------+-------------------------+-----------------------+---------------------+----------------------+
| 2019-01-19 00:00:00 | 18050 | 20813.18 | 18050 | NULL |
| 2019-01-12 00:00:00 | 18135 | 24768.43 | 18135 | NULL |
| 2019-01-10 09:00:27 | 80 | 1497.75 | 80 | NULL |
| 2019-01-09 09:20:55 | 51 | 933.50 | 51 | NULL |
| 2019-01-08 16:45:14 | 10 | 187.50 | 10 | NULL |
| 2019-01-05 18:21:00 | 17588 | 16968.49 | 17588 | NULL |
| 2018-12-29 00:00:00 | 17893 | 25404.18 | 17893 | NULL |
| 2018-12-28 15:23:04 | 1 | 35.00 | 1 | NULL |
| 2018-12-22 00:00:00 | 17353 | 17048.18 | 17353 | NULL |
| 2018-12-15 00:00:00 | 16893 | 10181.34 | 16893 | NULL |
| 2018-12-08 00:00:00 | 16220 | 99547.09 | 16220 | NULL |
| 2018-12-01 00:00:00 | 15476 | 87699.59 | 15476 | NULL |
+---------------------+-------------------------+-----------------------+---------------------+----------------------+
mysql mysql-5.6 query subquery
I have a query that need to show aggregated values in an already aggregated outer query.
Consider a query that fetches total count of accounts being credited on a certain day.
I would like to display
- total number orders
- Total orders that are "PENDING"
- Total orders that are "OPEN"
Here is the query that seems to make sense but as resultset show below, I am obviously not using the right approach. The "OPEN" column displays the entire total, the "PENDING" column stays NULL.
I feel I may be using the wrong approach, what are the options to have this work?
SELECT s.created, COUNT(s.id) 'total_accounts_credited', SUM(s.withdrawal) 'total_amount_credited',
(select count(s.id) WHERE s.status_id = 'OPEN') total_open_credited,
(select count(s.id) WHERE s.status_id = 'PENDING') total_pending_credited
FROM statements s
WHERE s.status_id in ('OPEN', 'PENDING')
GROUP BY
YEAR(s.created),
MONTH(s.created),
DAY(s.created)
ORDER BY s.created DESC
;
Results:
+---------------------+-------------------------+-----------------------+---------------------+----------------------+
| created | total_accounts_credited | total_amount_credited | total_open_credited | total_pending_credited |
+---------------------+-------------------------+-----------------------+---------------------+----------------------+
| 2019-01-19 00:00:00 | 18050 | 20813.18 | 18050 | NULL |
| 2019-01-12 00:00:00 | 18135 | 24768.43 | 18135 | NULL |
| 2019-01-10 09:00:27 | 80 | 1497.75 | 80 | NULL |
| 2019-01-09 09:20:55 | 51 | 933.50 | 51 | NULL |
| 2019-01-08 16:45:14 | 10 | 187.50 | 10 | NULL |
| 2019-01-05 18:21:00 | 17588 | 16968.49 | 17588 | NULL |
| 2018-12-29 00:00:00 | 17893 | 25404.18 | 17893 | NULL |
| 2018-12-28 15:23:04 | 1 | 35.00 | 1 | NULL |
| 2018-12-22 00:00:00 | 17353 | 17048.18 | 17353 | NULL |
| 2018-12-15 00:00:00 | 16893 | 10181.34 | 16893 | NULL |
| 2018-12-08 00:00:00 | 16220 | 99547.09 | 16220 | NULL |
| 2018-12-01 00:00:00 | 15476 | 87699.59 | 15476 | NULL |
+---------------------+-------------------------+-----------------------+---------------------+----------------------+
mysql mysql-5.6 query subquery
mysql mysql-5.6 query subquery
asked 5 hours ago
stefgosselinstefgosselin
1043
1043
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
SELECT ...,
SUM(s.status_id = 'OPEN') AS total_open_credited,
...
FROM ...
WHERE ...
GROUP BY DATE(s.created) -- a simplification
ORDER BY ...
Explanation: s.status_id = 'OPEN'
is a boolean expression that evaluates to TRUE or FALSE. TRUE is 1; FALSE is 0. Then SUM
correctly tallies what you asked for.
add a comment |
Your Answer
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "182"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: false,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: null,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fdba.stackexchange.com%2fquestions%2f227576%2fgetting-aggregate-sub-values-in-aggregate-query%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
SELECT ...,
SUM(s.status_id = 'OPEN') AS total_open_credited,
...
FROM ...
WHERE ...
GROUP BY DATE(s.created) -- a simplification
ORDER BY ...
Explanation: s.status_id = 'OPEN'
is a boolean expression that evaluates to TRUE or FALSE. TRUE is 1; FALSE is 0. Then SUM
correctly tallies what you asked for.
add a comment |
SELECT ...,
SUM(s.status_id = 'OPEN') AS total_open_credited,
...
FROM ...
WHERE ...
GROUP BY DATE(s.created) -- a simplification
ORDER BY ...
Explanation: s.status_id = 'OPEN'
is a boolean expression that evaluates to TRUE or FALSE. TRUE is 1; FALSE is 0. Then SUM
correctly tallies what you asked for.
add a comment |
SELECT ...,
SUM(s.status_id = 'OPEN') AS total_open_credited,
...
FROM ...
WHERE ...
GROUP BY DATE(s.created) -- a simplification
ORDER BY ...
Explanation: s.status_id = 'OPEN'
is a boolean expression that evaluates to TRUE or FALSE. TRUE is 1; FALSE is 0. Then SUM
correctly tallies what you asked for.
SELECT ...,
SUM(s.status_id = 'OPEN') AS total_open_credited,
...
FROM ...
WHERE ...
GROUP BY DATE(s.created) -- a simplification
ORDER BY ...
Explanation: s.status_id = 'OPEN'
is a boolean expression that evaluates to TRUE or FALSE. TRUE is 1; FALSE is 0. Then SUM
correctly tallies what you asked for.
answered 1 hour ago
Rick JamesRick James
41.5k22258
41.5k22258
add a comment |
add a comment |
Thanks for contributing an answer to Database Administrators Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fdba.stackexchange.com%2fquestions%2f227576%2fgetting-aggregate-sub-values-in-aggregate-query%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown