Additional column in unpivot/pivot

;with #unpivot_step2 as

(

    select reqid, Idno, RowNum, Item, Vals

    From 

        (

            select  

                    cast(reqid as varchar(150)) AS reqid,

                    cast(name collate database_default as varchar (150)) as name,

                    cast(idno collate database_default as varchar (150)) as idno,

                    cast(basicgroup collate database_default as varchar (150)) as basicgroup,

                    cast(industrialsector collate database_default as varchar (150)) as industrialsector,

                    cast(gender collate database_default as varchar (150)) as gender,

                    cast(income collate database_default as varchar (150)) as income,

                    cast(empname collate database_default as varchar(150)) as empname,

                    cast(emptyp collate database_default as varchar (150)) as emptyp,

                    row_number() over (partition by idno order by cast(date_created as datetime) desc) as RowNum

            from #mydatabase

        ) unpivot_table

    unpivot

        (

            vals for Item in (name, basicgroup, industrialsector, gender, income, empname, emptyp)

        ) unpivot_handle

)



select reqid, idno, Item,[2] as [From], [1] as [To]

FROM 

(

    select reqid, idno, rownum, Item, vals

    from #unpivot_step2

) pivot_table

pivot

(

    max (vals) for RowNum in ([1],[2])

) pivot_handle

where [1] <> [2]

With this script,I got as below result.

+-----------+--------------+------------------+----------------------+----------------------+

|   reqid   |     idno     |     colName      |      From_Value      |       To_Value       |

+-----------+--------------+------------------+----------------------+----------------------+

| 170916258 | 050505050505 | empname          |                      | YOLO                 |

| 170916258 | 050505050505 | emptyp           |                      | 113                  |

| 170916258 | 050505050505 | gender           | P                    |                      |

| 170916258 | 050505050505 | income           | 8891126              |                      |

| 170916258 | 050505050505 | name             | TEST2                | TEST3_2              |

| 170916258 | 100202025698 | gender           | L                    | P                    |

| 170916258 | 100202025698 | industrialsector | 01261                |                      |

| 170916258 | 100202025698 | name             | APPLICANT5_2         | CUST3_6              |

| 170916258 | 260404045698 | gender           |                      | P                    |

| 170916258 | 260404045698 | industrialsector |                      | 01279                |

| 170916258 | 260404045698 | name             | CUST4_3              | EHH4_4               |

+-----------+--------------+------------------+----------------------+----------------------+

How can I get result like below:

+-----------+---------+--------------+------------------+--------------+----------+

|   reqid   |  Name   |     idno     |     colName      |  From_Value  | To_Value |

+-----------+---------+--------------+------------------+--------------+----------+

| 170916258 | TEST3_2 |  50505050505 | empname          |              | YOLO     |

| 170916258 | TEST3_2 |  50505050505 | emptyp           |              | 113      |

| 170916258 | TEST3_2 |  50505050505 | gender           | P            |          |

| 170916258 | TEST3_2 |  50505050505 | income           | 8891126      |          |

| 170916258 | TEST3_2 |  50505050505 | name             | TEST2        | TEST3_2  |

| 170916258 | EHH4_4  | 100202025698 | gender           | L            | P        |

| 170916258 | EHH4_4  | 100202025698 | industrialsector | 1261         |          |

| 170916258 | EHH4_4  | 100202025698 | name             | APPLICANT5_2 | CUST3_6  |

| 170916258 | EHH4_4  | 260404045698 | gender           |              | P        |

| 170916258 | EHH4_4  | 260404045698 | industrialsector |              | 1279     |

| 170916258 | EHH4_4  | 260404045698 | name             | CUST4_3      | EHH4_4   |

+-----------+---------+--------------+------------------+--------------+----------+

I want additional column "NAME". Any idea how to enhance this script?

edited 3 mins ago

asked 19 hours ago

user3542587

New contributor

I want get 2 latest result to do comparison based on date and group by idno Add ROW_NUMBER() OVER (PARTITION BY IdNo ORDER BY date DESC). Take records where it is 1 or 2. Compare.

– Akina
19 hours ago

SQL Create Table/Insert Script It is wrong. 1) seqno .. PRIMARY KEY whereas you insert duplicates; 2) idno INTEGER whereas you insert values which needs at least 40 bit.

– Akina
19 hours ago

@Akina 1) seq_no it is a primary key, but the result need it duplicate as want to track this 1 application has how many people applying it and how frequent for changes. 2) i changed it to varchar(12), limit 12 digit only.

– user3542587
19 hours ago

seq_no it is a primary key, but the result What does the result? Look at your source data! Or at least try to execute your "SQL Create Table/Insert Script" on your server...

– Akina
18 hours ago

1

it is not very clear what you are asking for, besides the picture, if I need to put time to answer this, which is a pleasure for me, but at least I need to know more details, all the details in fact, to produce the desired result. After all, I am volunteering here.

– marcello miorelli
15 hours ago

|
show 6 more comments

;with #unpivot_step2 as

(

    select reqid, Idno, RowNum, Item, Vals

    From 

        (

            select  

                    cast(reqid as varchar(150)) AS reqid,

                    cast(name collate database_default as varchar (150)) as name,

                    cast(idno collate database_default as varchar (150)) as idno,

                    cast(basicgroup collate database_default as varchar (150)) as basicgroup,

                    cast(industrialsector collate database_default as varchar (150)) as industrialsector,

                    cast(gender collate database_default as varchar (150)) as gender,

                    cast(income collate database_default as varchar (150)) as income,

                    cast(empname collate database_default as varchar(150)) as empname,

                    cast(emptyp collate database_default as varchar (150)) as emptyp,

                    row_number() over (partition by idno order by cast(date_created as datetime) desc) as RowNum

            from #mydatabase

        ) unpivot_table

    unpivot

        (

            vals for Item in (name, basicgroup, industrialsector, gender, income, empname, emptyp)

        ) unpivot_handle

)



select reqid, idno, Item,[2] as [From], [1] as [To]

FROM 

(

    select reqid, idno, rownum, Item, vals

    from #unpivot_step2

) pivot_table

pivot

(

    max (vals) for RowNum in ([1],[2])

) pivot_handle

where [1] <> [2]

With this script,I got as below result.

+-----------+--------------+------------------+----------------------+----------------------+

|   reqid   |     idno     |     colName      |      From_Value      |       To_Value       |

+-----------+--------------+------------------+----------------------+----------------------+

| 170916258 | 050505050505 | empname          |                      | YOLO                 |

| 170916258 | 050505050505 | emptyp           |                      | 113                  |

| 170916258 | 050505050505 | gender           | P                    |                      |

| 170916258 | 050505050505 | income           | 8891126              |                      |

| 170916258 | 050505050505 | name             | TEST2                | TEST3_2              |

| 170916258 | 100202025698 | gender           | L                    | P                    |

| 170916258 | 100202025698 | industrialsector | 01261                |                      |

| 170916258 | 100202025698 | name             | APPLICANT5_2         | CUST3_6              |

| 170916258 | 260404045698 | gender           |                      | P                    |

| 170916258 | 260404045698 | industrialsector |                      | 01279                |

| 170916258 | 260404045698 | name             | CUST4_3              | EHH4_4               |

+-----------+--------------+------------------+----------------------+----------------------+

How can I get result like below:

+-----------+---------+--------------+------------------+--------------+----------+

|   reqid   |  Name   |     idno     |     colName      |  From_Value  | To_Value |

+-----------+---------+--------------+------------------+--------------+----------+

| 170916258 | TEST3_2 |  50505050505 | empname          |              | YOLO     |

| 170916258 | TEST3_2 |  50505050505 | emptyp           |              | 113      |

| 170916258 | TEST3_2 |  50505050505 | gender           | P            |          |

| 170916258 | TEST3_2 |  50505050505 | income           | 8891126      |          |

| 170916258 | TEST3_2 |  50505050505 | name             | TEST2        | TEST3_2  |

| 170916258 | EHH4_4  | 100202025698 | gender           | L            | P        |

| 170916258 | EHH4_4  | 100202025698 | industrialsector | 1261         |          |

| 170916258 | EHH4_4  | 100202025698 | name             | APPLICANT5_2 | CUST3_6  |

| 170916258 | EHH4_4  | 260404045698 | gender           |              | P        |

| 170916258 | EHH4_4  | 260404045698 | industrialsector |              | 1279     |

| 170916258 | EHH4_4  | 260404045698 | name             | CUST4_3      | EHH4_4   |

+-----------+---------+--------------+------------------+--------------+----------+

I want additional column "NAME". Any idea how to enhance this script?

edited 3 mins ago

asked 19 hours ago

user3542587

New contributor

I want get 2 latest result to do comparison based on date and group by idno Add ROW_NUMBER() OVER (PARTITION BY IdNo ORDER BY date DESC). Take records where it is 1 or 2. Compare.

– Akina
19 hours ago

SQL Create Table/Insert Script It is wrong. 1) seqno .. PRIMARY KEY whereas you insert duplicates; 2) idno INTEGER whereas you insert values which needs at least 40 bit.

– Akina
19 hours ago

@Akina 1) seq_no it is a primary key, but the result need it duplicate as want to track this 1 application has how many people applying it and how frequent for changes. 2) i changed it to varchar(12), limit 12 digit only.

– user3542587
19 hours ago

seq_no it is a primary key, but the result What does the result? Look at your source data! Or at least try to execute your "SQL Create Table/Insert Script" on your server...

– Akina
18 hours ago

1

it is not very clear what you are asking for, besides the picture, if I need to put time to answer this, which is a pleasure for me, but at least I need to know more details, all the details in fact, to produce the desired result. After all, I am volunteering here.

– marcello miorelli
15 hours ago

|
show 6 more comments

;with #unpivot_step2 as

(

    select reqid, Idno, RowNum, Item, Vals

    From 

        (

            select  

                    cast(reqid as varchar(150)) AS reqid,

                    cast(name collate database_default as varchar (150)) as name,

                    cast(idno collate database_default as varchar (150)) as idno,

                    cast(basicgroup collate database_default as varchar (150)) as basicgroup,

                    cast(industrialsector collate database_default as varchar (150)) as industrialsector,

                    cast(gender collate database_default as varchar (150)) as gender,

                    cast(income collate database_default as varchar (150)) as income,

                    cast(empname collate database_default as varchar(150)) as empname,

                    cast(emptyp collate database_default as varchar (150)) as emptyp,

                    row_number() over (partition by idno order by cast(date_created as datetime) desc) as RowNum

            from #mydatabase

        ) unpivot_table

    unpivot

        (

            vals for Item in (name, basicgroup, industrialsector, gender, income, empname, emptyp)

        ) unpivot_handle

)



select reqid, idno, Item,[2] as [From], [1] as [To]

FROM 

(

    select reqid, idno, rownum, Item, vals

    from #unpivot_step2

) pivot_table

pivot

(

    max (vals) for RowNum in ([1],[2])

) pivot_handle

where [1] <> [2]

With this script,I got as below result.

+-----------+--------------+------------------+----------------------+----------------------+

|   reqid   |     idno     |     colName      |      From_Value      |       To_Value       |

+-----------+--------------+------------------+----------------------+----------------------+

| 170916258 | 050505050505 | empname          |                      | YOLO                 |

| 170916258 | 050505050505 | emptyp           |                      | 113                  |

| 170916258 | 050505050505 | gender           | P                    |                      |

| 170916258 | 050505050505 | income           | 8891126              |                      |

| 170916258 | 050505050505 | name             | TEST2                | TEST3_2              |

| 170916258 | 100202025698 | gender           | L                    | P                    |

| 170916258 | 100202025698 | industrialsector | 01261                |                      |

| 170916258 | 100202025698 | name             | APPLICANT5_2         | CUST3_6              |

| 170916258 | 260404045698 | gender           |                      | P                    |

| 170916258 | 260404045698 | industrialsector |                      | 01279                |

| 170916258 | 260404045698 | name             | CUST4_3              | EHH4_4               |

+-----------+--------------+------------------+----------------------+----------------------+

How can I get result like below:

+-----------+---------+--------------+------------------+--------------+----------+

|   reqid   |  Name   |     idno     |     colName      |  From_Value  | To_Value |

+-----------+---------+--------------+------------------+--------------+----------+

| 170916258 | TEST3_2 |  50505050505 | empname          |              | YOLO     |

| 170916258 | TEST3_2 |  50505050505 | emptyp           |              | 113      |

| 170916258 | TEST3_2 |  50505050505 | gender           | P            |          |

| 170916258 | TEST3_2 |  50505050505 | income           | 8891126      |          |

| 170916258 | TEST3_2 |  50505050505 | name             | TEST2        | TEST3_2  |

| 170916258 | EHH4_4  | 100202025698 | gender           | L            | P        |

| 170916258 | EHH4_4  | 100202025698 | industrialsector | 1261         |          |

| 170916258 | EHH4_4  | 100202025698 | name             | APPLICANT5_2 | CUST3_6  |

| 170916258 | EHH4_4  | 260404045698 | gender           |              | P        |

| 170916258 | EHH4_4  | 260404045698 | industrialsector |              | 1279     |

| 170916258 | EHH4_4  | 260404045698 | name             | CUST4_3      | EHH4_4   |

+-----------+---------+--------------+------------------+--------------+----------+

I want additional column "NAME". Any idea how to enhance this script?

edited 3 mins ago

asked 19 hours ago

user3542587

New contributor

;with #unpivot_step2 as

(

    select reqid, Idno, RowNum, Item, Vals

    From 

        (

            select  

                    cast(reqid as varchar(150)) AS reqid,

                    cast(name collate database_default as varchar (150)) as name,

                    cast(idno collate database_default as varchar (150)) as idno,

                    cast(basicgroup collate database_default as varchar (150)) as basicgroup,

                    cast(industrialsector collate database_default as varchar (150)) as industrialsector,

                    cast(gender collate database_default as varchar (150)) as gender,

                    cast(income collate database_default as varchar (150)) as income,

                    cast(empname collate database_default as varchar(150)) as empname,

                    cast(emptyp collate database_default as varchar (150)) as emptyp,

                    row_number() over (partition by idno order by cast(date_created as datetime) desc) as RowNum

            from #mydatabase

        ) unpivot_table

    unpivot

        (

            vals for Item in (name, basicgroup, industrialsector, gender, income, empname, emptyp)

        ) unpivot_handle

)



select reqid, idno, Item,[2] as [From], [1] as [To]

FROM 

(

    select reqid, idno, rownum, Item, vals

    from #unpivot_step2

) pivot_table

pivot

(

    max (vals) for RowNum in ([1],[2])

) pivot_handle

where [1] <> [2]

With this script,I got as below result.

+-----------+--------------+------------------+----------------------+----------------------+

|   reqid   |     idno     |     colName      |      From_Value      |       To_Value       |

+-----------+--------------+------------------+----------------------+----------------------+

| 170916258 | 050505050505 | empname          |                      | YOLO                 |

| 170916258 | 050505050505 | emptyp           |                      | 113                  |

| 170916258 | 050505050505 | gender           | P                    |                      |

| 170916258 | 050505050505 | income           | 8891126              |                      |

| 170916258 | 050505050505 | name             | TEST2                | TEST3_2              |

| 170916258 | 100202025698 | gender           | L                    | P                    |

| 170916258 | 100202025698 | industrialsector | 01261                |                      |

| 170916258 | 100202025698 | name             | APPLICANT5_2         | CUST3_6              |

| 170916258 | 260404045698 | gender           |                      | P                    |

| 170916258 | 260404045698 | industrialsector |                      | 01279                |

| 170916258 | 260404045698 | name             | CUST4_3              | EHH4_4               |

+-----------+--------------+------------------+----------------------+----------------------+

How can I get result like below:

+-----------+---------+--------------+------------------+--------------+----------+

|   reqid   |  Name   |     idno     |     colName      |  From_Value  | To_Value |

+-----------+---------+--------------+------------------+--------------+----------+

| 170916258 | TEST3_2 |  50505050505 | empname          |              | YOLO     |

| 170916258 | TEST3_2 |  50505050505 | emptyp           |              | 113      |

| 170916258 | TEST3_2 |  50505050505 | gender           | P            |          |

| 170916258 | TEST3_2 |  50505050505 | income           | 8891126      |          |

| 170916258 | TEST3_2 |  50505050505 | name             | TEST2        | TEST3_2  |

| 170916258 | EHH4_4  | 100202025698 | gender           | L            | P        |

| 170916258 | EHH4_4  | 100202025698 | industrialsector | 1261         |          |

| 170916258 | EHH4_4  | 100202025698 | name             | APPLICANT5_2 | CUST3_6  |

| 170916258 | EHH4_4  | 260404045698 | gender           |              | P        |

| 170916258 | EHH4_4  | 260404045698 | industrialsector |              | 1279     |

| 170916258 | EHH4_4  | 260404045698 | name             | CUST4_3      | EHH4_4   |

+-----------+---------+--------------+------------------+--------------+----------+

I want additional column "NAME". Any idea how to enhance this script?

sql-server sql-server-2012

edited 3 mins ago

asked 19 hours ago

user3542587

New contributor

edited 3 mins ago

asked 19 hours ago

user3542587

New contributor

edited 3 mins ago

asked 19 hours ago

user3542587

New contributor

asked 19 hours ago

user3542587

asked 19 hours ago

user3542587

New contributor

user3542587 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

I want get 2 latest result to do comparison based on date and group by idno Add ROW_NUMBER() OVER (PARTITION BY IdNo ORDER BY date DESC). Take records where it is 1 or 2. Compare.

– Akina
19 hours ago

SQL Create Table/Insert Script It is wrong. 1) seqno .. PRIMARY KEY whereas you insert duplicates; 2) idno INTEGER whereas you insert values which needs at least 40 bit.

– Akina
19 hours ago

@Akina 1) seq_no it is a primary key, but the result need it duplicate as want to track this 1 application has how many people applying it and how frequent for changes. 2) i changed it to varchar(12), limit 12 digit only.

– user3542587
19 hours ago

seq_no it is a primary key, but the result What does the result? Look at your source data! Or at least try to execute your "SQL Create Table/Insert Script" on your server...

– Akina
18 hours ago

1

it is not very clear what you are asking for, besides the picture, if I need to put time to answer this, which is a pleasure for me, but at least I need to know more details, all the details in fact, to produce the desired result. After all, I am volunteering here.

– marcello miorelli
15 hours ago

|
show 6 more comments

I want get 2 latest result to do comparison based on date and group by idno Add ROW_NUMBER() OVER (PARTITION BY IdNo ORDER BY date DESC). Take records where it is 1 or 2. Compare.

– Akina
19 hours ago

SQL Create Table/Insert Script It is wrong. 1) seqno .. PRIMARY KEY whereas you insert duplicates; 2) idno INTEGER whereas you insert values which needs at least 40 bit.

– Akina
19 hours ago

@Akina 1) seq_no it is a primary key, but the result need it duplicate as want to track this 1 application has how many people applying it and how frequent for changes. 2) i changed it to varchar(12), limit 12 digit only.

– user3542587
19 hours ago

seq_no it is a primary key, but the result What does the result? Look at your source data! Or at least try to execute your "SQL Create Table/Insert Script" on your server...

– Akina
18 hours ago

1

it is not very clear what you are asking for, besides the picture, if I need to put time to answer this, which is a pleasure for me, but at least I need to know more details, all the details in fact, to produce the desired result. After all, I am volunteering here.

– marcello miorelli
15 hours ago

I want get 2 latest result to do comparison based on date and group by idno Add ROW_NUMBER() OVER (PARTITION BY IdNo ORDER BY date DESC). Take records where it is 1 or 2. Compare.

– Akina
19 hours ago

SQL Create Table/Insert Script It is wrong. 1) seqno .. PRIMARY KEY whereas you insert duplicates; 2) idno INTEGER whereas you insert values which needs at least 40 bit.

– Akina
19 hours ago

@Akina 1) seq_no it is a primary key, but the result need it duplicate as want to track this 1 application has how many people applying it and how frequent for changes. 2) i changed it to varchar(12), limit 12 digit only.

– user3542587
19 hours ago

seq_no it is a primary key, but the result What does the result? Look at your source data! Or at least try to execute your "SQL Create Table/Insert Script" on your server...

– Akina
18 hours ago

it is not very clear what you are asking for, besides the picture, if I need to put time to answer this, which is a pleasure for me, but at least I need to know more details, all the details in fact, to produce the desired result. After all, I am volunteering here.

– marcello miorelli
15 hours ago

|
show 6 more comments

0

active

oldest

votes

Your Answer

StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "182"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);

StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});

function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: false,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: null,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});

}
});

user3542587 is a new contributor. Be nice, and check out our Code of Conduct.

draft saved

draft discarded

Sign up or log in

StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});

Post as a guest

Name

Required, but never shown

StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fdba.stackexchange.com%2fquestions%2f231031%2fadditional-column-in-unpivot-pivot%23new-answer', 'question_page');
}
);

Post as a guest

Name

Required, but never shown

0

active

oldest

votes

0

active

oldest

votes

user3542587 is a new contributor. Be nice, and check out our Code of Conduct.

draft saved

draft discarded

user3542587 is a new contributor. Be nice, and check out our Code of Conduct.

Thanks for contributing an answer to Database Administrators Stack Exchange!

Please be sure to answer the question. Provide details and share your research!

But avoid …

Asking for help, clarification, or responding to other answers.

Making statements based on opinion; back them up with references or personal experience.

To learn more, see our tips on writing great answers.

draft saved

draft discarded

Sign up or log in

StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});

Post as a guest

Name

Required, but never shown

Post as a guest

Name

Required, but never shown

Sign up or log in

StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});

Post as a guest

Name

Required, but never shown

Sign up or log in

StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});

Post as a guest

Name

Required, but never shown

Sign up or log in

StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});

Post as a guest

Name

Required, but never shown

Name

Required, but never shown

Name

Required, but never shown

This page is only for reference, If you need detailed information, please check here

搜尋此網誌

Xrhrft