Partitioning on a computed column
Using - Oracle 11g
I have created a table say X. of this table, a column say C3 is a computed column which will have a value based on incoming values for the other 2 columns say C1 and C2. I am using a BEFORE INSERT trigger for the same.
The table is partitioned by Range on the computed column C3 and this is a Date column.
Now, when I try to insert data into the computed column using a Trigger, the system dumps all data into the default partition rather than creating individual partitions. Instead, when I use the computation formula directly in my Insert query; the partitioning is fine and as expected.
Any idea?
Thanx
oracle oracle-11g
edited Feb 17 '15 at 14:28
LowlyDBA
6,98252542
asked Feb 17 '15 at 13:24
user58733user58733
1
bumped to the homepage by Community♦ 11 mins ago
This question has answers that may be good or bad; the system has marked it active so that they can be reviewed.
add a comment |
Using - Oracle 11g
I have created a table say X. of this table, a column say C3 is a computed column which will have a value based on incoming values for the other 2 columns say C1 and C2. I am using a BEFORE INSERT trigger for the same.
The table is partitioned by Range on the computed column C3 and this is a Date column.
Now, when I try to insert data into the computed column using a Trigger, the system dumps all data into the default partition rather than creating individual partitions. Instead, when I use the computation formula directly in my Insert query; the partitioning is fine and as expected.
Any idea?
Thanx
oracle oracle-11g
edited Feb 17 '15 at 14:28
LowlyDBA
6,98252542
asked Feb 17 '15 at 13:24
user58733user58733
1
bumped to the homepage by Community♦ 11 mins ago
This question has answers that may be good or bad; the system has marked it active so that they can be reviewed.
add a comment |
Using - Oracle 11g
I have created a table say X. of this table, a column say C3 is a computed column which will have a value based on incoming values for the other 2 columns say C1 and C2. I am using a BEFORE INSERT trigger for the same.
The table is partitioned by Range on the computed column C3 and this is a Date column.
Now, when I try to insert data into the computed column using a Trigger, the system dumps all data into the default partition rather than creating individual partitions. Instead, when I use the computation formula directly in my Insert query; the partitioning is fine and as expected.
Any idea?
Thanx
oracle oracle-11g
edited Feb 17 '15 at 14:28
LowlyDBA
6,98252542
asked Feb 17 '15 at 13:24
user58733user58733
1
Using - Oracle 11g
I have created a table say X. of this table, a column say C3 is a computed column which will have a value based on incoming values for the other 2 columns say C1 and C2. I am using a BEFORE INSERT trigger for the same.
The table is partitioned by Range on the computed column C3 and this is a Date column.
Now, when I try to insert data into the computed column using a Trigger, the system dumps all data into the default partition rather than creating individual partitions. Instead, when I use the computation formula directly in my Insert query; the partitioning is fine and as expected.
Any idea?
Thanx
oracle oracle-11g
oracle oracle-11g
edited Feb 17 '15 at 14:28
LowlyDBA
6,98252542
asked Feb 17 '15 at 13:24
user58733user58733
1
edited Feb 17 '15 at 14:28
LowlyDBA
6,98252542
asked Feb 17 '15 at 13:24
user58733user58733
1
edited Feb 17 '15 at 14:28
LowlyDBA
6,98252542
edited Feb 17 '15 at 14:28
LowlyDBA
6,98252542
edited Feb 17 '15 at 14:28
LowlyDBA
6,98252542
6,98252542
asked Feb 17 '15 at 13:24
user58733user58733
1
asked Feb 17 '15 at 13:24
user58733user58733
1
asked Feb 17 '15 at 13:24
user58733user58733
1
1
bumped to the homepage by Community♦ 11 mins ago
This question has answers that may be good or bad; the system has marked it active so that they can be reviewed.
bumped to the homepage by Community♦ 11 mins ago
This question has answers that may be good or bad; the system has marked it active so that they can be reviewed.
add a comment |
add a comment |
1 Answer
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I sounds like you are doing partitioning based on a virtual column.
virtual_column_based_partitioning
answered Feb 17 '15 at 14:04
Gandolf989Gandolf989
1,218512
add a comment |
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I sounds like you are doing partitioning based on a virtual column.
virtual_column_based_partitioning
answered Feb 17 '15 at 14:04
Gandolf989Gandolf989
1,218512
add a comment |
I sounds like you are doing partitioning based on a virtual column.
virtual_column_based_partitioning
answered Feb 17 '15 at 14:04
Gandolf989Gandolf989
1,218512
add a comment |
I sounds like you are doing partitioning based on a virtual column.
virtual_column_based_partitioning
answered Feb 17 '15 at 14:04
Gandolf989Gandolf989
1,218512
I sounds like you are doing partitioning based on a virtual column.
virtual_column_based_partitioning
answered Feb 17 '15 at 14:04
Gandolf989Gandolf989
1,218512
answered Feb 17 '15 at 14:04
Gandolf989Gandolf989
1,218512
answered Feb 17 '15 at 14:04
Gandolf989Gandolf989
1,218512
answered Feb 17 '15 at 14:04
Gandolf989Gandolf989
1,218512
1,218512
add a comment |
add a comment |
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