MySQL optimizer won't use my index
With the following query:
SELECT
*
FROM
geoname
LEFT JOIN alternatename
ON geoname.geonameid = alternatename.geonameid
AND alternatename.isPreferredName = 1
AND alternatename.isoLanguage = 'es'
WHERE
geoname.fcode = 'ADM2'
AND geoname.country = 'ES'
I get the following execution plan:
+----+-------------+---------------+------+-----------------------------------------+--------------------+---------+----------------------------------+------+-----------------------+
| id | select_type | table | type | possible_keys | key | key_len | ref | rows | Extra |
+----+-------------+---------------+------+-----------------------------------------+--------------------+---------+----------------------------------+------+-----------------------+
| 1 | SIMPLE | geoname | ref | fcode_idx,country_idx,fcode_country_idx | fcode_country_idx | 42 | const,const | 51 | Using index condition |
| 1 | SIMPLE | alternatename | ref | IDX_8F82EED4E2097D,idx_geoid_lang_pref | IDX_8F82EED4E2097D | 4 | acme_geonames.geoname.geonameid | 1 | Using where |
+----+-------------+---------------+------+-----------------------------------------+--------------------+---------+----------------------------------+------+-----------------------+
The IDX_8F82EED4E2097D
is on the geonameid
field only, while the idx_geoid_lang_pref
index is on the fields:
geonameid
isPreferredName
isoLanguage
Why doesn't MySQL use the idx_geoid_lang_pref
index for the alternatename
join, which I made specifically for this query?
Update as asked in comments:
the exact version of MySQL
5.6.24
what are the tables sizes?
- geoname: 4.082.489 rows
- alternatename: 2.558.890 rows
How many rows does the query return?
52
How much time does it need to run?
0:00:0.00142580
according to QueryStats
Note: my goal is not to speed up this particular request, only to understand why an index which cover the exact fields of the query is not chosen by the optimizer.
Provide the full SHOW CREATE TABLE statement for each table
CREATE TABLE `geoname` (
`geonameid` int(11) NOT NULL AUTO_INCREMENT,
`name` varchar(200) COLLATE utf8_unicode_ci NOT NULL,
`asciiname` varchar(200) COLLATE utf8_unicode_ci DEFAULT NULL,
`latitude` decimal(10,7) DEFAULT NULL,
`longitude` decimal(10,7) DEFAULT NULL,
`fclass` char(1) COLLATE utf8_unicode_ci DEFAULT NULL,
`fcode` varchar(10) COLLATE utf8_unicode_ci DEFAULT NULL,
`country` varchar(2) COLLATE utf8_unicode_ci DEFAULT NULL,
`cc2` varchar(60) COLLATE utf8_unicode_ci DEFAULT NULL,
`admin1` varchar(20) COLLATE utf8_unicode_ci DEFAULT NULL,
`admin2` varchar(80) COLLATE utf8_unicode_ci DEFAULT NULL,
`admin3` varchar(20) COLLATE utf8_unicode_ci DEFAULT NULL,
`admin4` varchar(20) COLLATE utf8_unicode_ci DEFAULT NULL,
`population` int(11) DEFAULT NULL,
`elevation` int(11) DEFAULT NULL,
`gtopo30` int(11) DEFAULT NULL,
`timezone` varchar(40) COLLATE utf8_unicode_ci DEFAULT NULL,
`moddate` date DEFAULT NULL,
PRIMARY KEY (`geonameid`),
KEY `fclass_idx` (`fclass`),
KEY `fcode_idx` (`fcode`),
KEY `country_idx` (`country`),
KEY `admin1_idx` (`admin1`),
KEY `admin2_idx` (`admin2`),
KEY `fcode_country_idx` (`fcode`,`country`)
) ENGINE=InnoDB AUTO_INCREMENT=10346797 DEFAULT CHARSET=utf8 COLLATE=utf8_unicode_ci;
CREATE TABLE `alternatename` (
`alternatenameId` int(11) NOT NULL AUTO_INCREMENT,
`geonameid` int(11) NOT NULL,
`isoLanguage` varchar(7) COLLATE utf8_unicode_ci NOT NULL,
`alternateName` varchar(200) COLLATE utf8_unicode_ci NOT NULL,
`isPreferredName` tinyint(1) NOT NULL,
`isShortName` tinyint(1) NOT NULL,
`isColloquial` tinyint(1) NOT NULL,
`isHistoric` tinyint(1) NOT NULL,
PRIMARY KEY (`alternatenameId`),
KEY `IDX_8F82EED4E2097D` (`geonameid`),
KEY `idx_geoid_lang_pref` (`geonameid`,`isPreferredName`,`isoLanguage`),
CONSTRAINT `FK_8F82EED4E2097D` FOREIGN KEY (`geonameid`) REFERENCES `geoname` (`geonameid`)
) ENGINE=InnoDB AUTO_INCREMENT=10842837 DEFAULT CHARSET=utf8 COLLATE=utf8_unicode_ci;
mysql join execution-plan explain
bumped to the homepage by Community♦ 12 mins ago
This question has answers that may be good or bad; the system has marked it active so that they can be reviewed.
|
show 4 more comments
With the following query:
SELECT
*
FROM
geoname
LEFT JOIN alternatename
ON geoname.geonameid = alternatename.geonameid
AND alternatename.isPreferredName = 1
AND alternatename.isoLanguage = 'es'
WHERE
geoname.fcode = 'ADM2'
AND geoname.country = 'ES'
I get the following execution plan:
+----+-------------+---------------+------+-----------------------------------------+--------------------+---------+----------------------------------+------+-----------------------+
| id | select_type | table | type | possible_keys | key | key_len | ref | rows | Extra |
+----+-------------+---------------+------+-----------------------------------------+--------------------+---------+----------------------------------+------+-----------------------+
| 1 | SIMPLE | geoname | ref | fcode_idx,country_idx,fcode_country_idx | fcode_country_idx | 42 | const,const | 51 | Using index condition |
| 1 | SIMPLE | alternatename | ref | IDX_8F82EED4E2097D,idx_geoid_lang_pref | IDX_8F82EED4E2097D | 4 | acme_geonames.geoname.geonameid | 1 | Using where |
+----+-------------+---------------+------+-----------------------------------------+--------------------+---------+----------------------------------+------+-----------------------+
The IDX_8F82EED4E2097D
is on the geonameid
field only, while the idx_geoid_lang_pref
index is on the fields:
geonameid
isPreferredName
isoLanguage
Why doesn't MySQL use the idx_geoid_lang_pref
index for the alternatename
join, which I made specifically for this query?
Update as asked in comments:
the exact version of MySQL
5.6.24
what are the tables sizes?
- geoname: 4.082.489 rows
- alternatename: 2.558.890 rows
How many rows does the query return?
52
How much time does it need to run?
0:00:0.00142580
according to QueryStats
Note: my goal is not to speed up this particular request, only to understand why an index which cover the exact fields of the query is not chosen by the optimizer.
Provide the full SHOW CREATE TABLE statement for each table
CREATE TABLE `geoname` (
`geonameid` int(11) NOT NULL AUTO_INCREMENT,
`name` varchar(200) COLLATE utf8_unicode_ci NOT NULL,
`asciiname` varchar(200) COLLATE utf8_unicode_ci DEFAULT NULL,
`latitude` decimal(10,7) DEFAULT NULL,
`longitude` decimal(10,7) DEFAULT NULL,
`fclass` char(1) COLLATE utf8_unicode_ci DEFAULT NULL,
`fcode` varchar(10) COLLATE utf8_unicode_ci DEFAULT NULL,
`country` varchar(2) COLLATE utf8_unicode_ci DEFAULT NULL,
`cc2` varchar(60) COLLATE utf8_unicode_ci DEFAULT NULL,
`admin1` varchar(20) COLLATE utf8_unicode_ci DEFAULT NULL,
`admin2` varchar(80) COLLATE utf8_unicode_ci DEFAULT NULL,
`admin3` varchar(20) COLLATE utf8_unicode_ci DEFAULT NULL,
`admin4` varchar(20) COLLATE utf8_unicode_ci DEFAULT NULL,
`population` int(11) DEFAULT NULL,
`elevation` int(11) DEFAULT NULL,
`gtopo30` int(11) DEFAULT NULL,
`timezone` varchar(40) COLLATE utf8_unicode_ci DEFAULT NULL,
`moddate` date DEFAULT NULL,
PRIMARY KEY (`geonameid`),
KEY `fclass_idx` (`fclass`),
KEY `fcode_idx` (`fcode`),
KEY `country_idx` (`country`),
KEY `admin1_idx` (`admin1`),
KEY `admin2_idx` (`admin2`),
KEY `fcode_country_idx` (`fcode`,`country`)
) ENGINE=InnoDB AUTO_INCREMENT=10346797 DEFAULT CHARSET=utf8 COLLATE=utf8_unicode_ci;
CREATE TABLE `alternatename` (
`alternatenameId` int(11) NOT NULL AUTO_INCREMENT,
`geonameid` int(11) NOT NULL,
`isoLanguage` varchar(7) COLLATE utf8_unicode_ci NOT NULL,
`alternateName` varchar(200) COLLATE utf8_unicode_ci NOT NULL,
`isPreferredName` tinyint(1) NOT NULL,
`isShortName` tinyint(1) NOT NULL,
`isColloquial` tinyint(1) NOT NULL,
`isHistoric` tinyint(1) NOT NULL,
PRIMARY KEY (`alternatenameId`),
KEY `IDX_8F82EED4E2097D` (`geonameid`),
KEY `idx_geoid_lang_pref` (`geonameid`,`isPreferredName`,`isoLanguage`),
CONSTRAINT `FK_8F82EED4E2097D` FOREIGN KEY (`geonameid`) REFERENCES `geoname` (`geonameid`)
) ENGINE=InnoDB AUTO_INCREMENT=10842837 DEFAULT CHARSET=utf8 COLLATE=utf8_unicode_ci;
mysql join execution-plan explain
bumped to the homepage by Community♦ 12 mins ago
This question has answers that may be good or bad; the system has marked it active so that they can be reviewed.
1
I sure, correct answer for question - WHY? no body excluding few guys from Oracle/Percona/MariaDB who wrote query optimisation can not answer :) different versions of MySQL have different query optimisation algorythms also. if You want test it with other index - test it with FORCE index hint
– a_vlad
Nov 17 '15 at 11:32
I would suggest an index with different order:(isPreferredName, isoLanguage, geonameid)
– ypercubeᵀᴹ
Nov 17 '15 at 11:34
But you haven't provided with the exact version of MySQL (as @a_vlad pointed). And what are the tables sizes? How many rows does the query return? How much time does it need to run?
– ypercubeᵀᴹ
Nov 17 '15 at 11:37
Thanks for your comments, I updated my question with the data you asked.
– marcv
Nov 17 '15 at 11:55
1
I wonder why there is a question there. The query returns the answer (52 rows) in about a millisecond. Why would anyone care what indexes it uses?
– ypercubeᵀᴹ
Nov 17 '15 at 12:05
|
show 4 more comments
With the following query:
SELECT
*
FROM
geoname
LEFT JOIN alternatename
ON geoname.geonameid = alternatename.geonameid
AND alternatename.isPreferredName = 1
AND alternatename.isoLanguage = 'es'
WHERE
geoname.fcode = 'ADM2'
AND geoname.country = 'ES'
I get the following execution plan:
+----+-------------+---------------+------+-----------------------------------------+--------------------+---------+----------------------------------+------+-----------------------+
| id | select_type | table | type | possible_keys | key | key_len | ref | rows | Extra |
+----+-------------+---------------+------+-----------------------------------------+--------------------+---------+----------------------------------+------+-----------------------+
| 1 | SIMPLE | geoname | ref | fcode_idx,country_idx,fcode_country_idx | fcode_country_idx | 42 | const,const | 51 | Using index condition |
| 1 | SIMPLE | alternatename | ref | IDX_8F82EED4E2097D,idx_geoid_lang_pref | IDX_8F82EED4E2097D | 4 | acme_geonames.geoname.geonameid | 1 | Using where |
+----+-------------+---------------+------+-----------------------------------------+--------------------+---------+----------------------------------+------+-----------------------+
The IDX_8F82EED4E2097D
is on the geonameid
field only, while the idx_geoid_lang_pref
index is on the fields:
geonameid
isPreferredName
isoLanguage
Why doesn't MySQL use the idx_geoid_lang_pref
index for the alternatename
join, which I made specifically for this query?
Update as asked in comments:
the exact version of MySQL
5.6.24
what are the tables sizes?
- geoname: 4.082.489 rows
- alternatename: 2.558.890 rows
How many rows does the query return?
52
How much time does it need to run?
0:00:0.00142580
according to QueryStats
Note: my goal is not to speed up this particular request, only to understand why an index which cover the exact fields of the query is not chosen by the optimizer.
Provide the full SHOW CREATE TABLE statement for each table
CREATE TABLE `geoname` (
`geonameid` int(11) NOT NULL AUTO_INCREMENT,
`name` varchar(200) COLLATE utf8_unicode_ci NOT NULL,
`asciiname` varchar(200) COLLATE utf8_unicode_ci DEFAULT NULL,
`latitude` decimal(10,7) DEFAULT NULL,
`longitude` decimal(10,7) DEFAULT NULL,
`fclass` char(1) COLLATE utf8_unicode_ci DEFAULT NULL,
`fcode` varchar(10) COLLATE utf8_unicode_ci DEFAULT NULL,
`country` varchar(2) COLLATE utf8_unicode_ci DEFAULT NULL,
`cc2` varchar(60) COLLATE utf8_unicode_ci DEFAULT NULL,
`admin1` varchar(20) COLLATE utf8_unicode_ci DEFAULT NULL,
`admin2` varchar(80) COLLATE utf8_unicode_ci DEFAULT NULL,
`admin3` varchar(20) COLLATE utf8_unicode_ci DEFAULT NULL,
`admin4` varchar(20) COLLATE utf8_unicode_ci DEFAULT NULL,
`population` int(11) DEFAULT NULL,
`elevation` int(11) DEFAULT NULL,
`gtopo30` int(11) DEFAULT NULL,
`timezone` varchar(40) COLLATE utf8_unicode_ci DEFAULT NULL,
`moddate` date DEFAULT NULL,
PRIMARY KEY (`geonameid`),
KEY `fclass_idx` (`fclass`),
KEY `fcode_idx` (`fcode`),
KEY `country_idx` (`country`),
KEY `admin1_idx` (`admin1`),
KEY `admin2_idx` (`admin2`),
KEY `fcode_country_idx` (`fcode`,`country`)
) ENGINE=InnoDB AUTO_INCREMENT=10346797 DEFAULT CHARSET=utf8 COLLATE=utf8_unicode_ci;
CREATE TABLE `alternatename` (
`alternatenameId` int(11) NOT NULL AUTO_INCREMENT,
`geonameid` int(11) NOT NULL,
`isoLanguage` varchar(7) COLLATE utf8_unicode_ci NOT NULL,
`alternateName` varchar(200) COLLATE utf8_unicode_ci NOT NULL,
`isPreferredName` tinyint(1) NOT NULL,
`isShortName` tinyint(1) NOT NULL,
`isColloquial` tinyint(1) NOT NULL,
`isHistoric` tinyint(1) NOT NULL,
PRIMARY KEY (`alternatenameId`),
KEY `IDX_8F82EED4E2097D` (`geonameid`),
KEY `idx_geoid_lang_pref` (`geonameid`,`isPreferredName`,`isoLanguage`),
CONSTRAINT `FK_8F82EED4E2097D` FOREIGN KEY (`geonameid`) REFERENCES `geoname` (`geonameid`)
) ENGINE=InnoDB AUTO_INCREMENT=10842837 DEFAULT CHARSET=utf8 COLLATE=utf8_unicode_ci;
mysql join execution-plan explain
With the following query:
SELECT
*
FROM
geoname
LEFT JOIN alternatename
ON geoname.geonameid = alternatename.geonameid
AND alternatename.isPreferredName = 1
AND alternatename.isoLanguage = 'es'
WHERE
geoname.fcode = 'ADM2'
AND geoname.country = 'ES'
I get the following execution plan:
+----+-------------+---------------+------+-----------------------------------------+--------------------+---------+----------------------------------+------+-----------------------+
| id | select_type | table | type | possible_keys | key | key_len | ref | rows | Extra |
+----+-------------+---------------+------+-----------------------------------------+--------------------+---------+----------------------------------+------+-----------------------+
| 1 | SIMPLE | geoname | ref | fcode_idx,country_idx,fcode_country_idx | fcode_country_idx | 42 | const,const | 51 | Using index condition |
| 1 | SIMPLE | alternatename | ref | IDX_8F82EED4E2097D,idx_geoid_lang_pref | IDX_8F82EED4E2097D | 4 | acme_geonames.geoname.geonameid | 1 | Using where |
+----+-------------+---------------+------+-----------------------------------------+--------------------+---------+----------------------------------+------+-----------------------+
The IDX_8F82EED4E2097D
is on the geonameid
field only, while the idx_geoid_lang_pref
index is on the fields:
geonameid
isPreferredName
isoLanguage
Why doesn't MySQL use the idx_geoid_lang_pref
index for the alternatename
join, which I made specifically for this query?
Update as asked in comments:
the exact version of MySQL
5.6.24
what are the tables sizes?
- geoname: 4.082.489 rows
- alternatename: 2.558.890 rows
How many rows does the query return?
52
How much time does it need to run?
0:00:0.00142580
according to QueryStats
Note: my goal is not to speed up this particular request, only to understand why an index which cover the exact fields of the query is not chosen by the optimizer.
Provide the full SHOW CREATE TABLE statement for each table
CREATE TABLE `geoname` (
`geonameid` int(11) NOT NULL AUTO_INCREMENT,
`name` varchar(200) COLLATE utf8_unicode_ci NOT NULL,
`asciiname` varchar(200) COLLATE utf8_unicode_ci DEFAULT NULL,
`latitude` decimal(10,7) DEFAULT NULL,
`longitude` decimal(10,7) DEFAULT NULL,
`fclass` char(1) COLLATE utf8_unicode_ci DEFAULT NULL,
`fcode` varchar(10) COLLATE utf8_unicode_ci DEFAULT NULL,
`country` varchar(2) COLLATE utf8_unicode_ci DEFAULT NULL,
`cc2` varchar(60) COLLATE utf8_unicode_ci DEFAULT NULL,
`admin1` varchar(20) COLLATE utf8_unicode_ci DEFAULT NULL,
`admin2` varchar(80) COLLATE utf8_unicode_ci DEFAULT NULL,
`admin3` varchar(20) COLLATE utf8_unicode_ci DEFAULT NULL,
`admin4` varchar(20) COLLATE utf8_unicode_ci DEFAULT NULL,
`population` int(11) DEFAULT NULL,
`elevation` int(11) DEFAULT NULL,
`gtopo30` int(11) DEFAULT NULL,
`timezone` varchar(40) COLLATE utf8_unicode_ci DEFAULT NULL,
`moddate` date DEFAULT NULL,
PRIMARY KEY (`geonameid`),
KEY `fclass_idx` (`fclass`),
KEY `fcode_idx` (`fcode`),
KEY `country_idx` (`country`),
KEY `admin1_idx` (`admin1`),
KEY `admin2_idx` (`admin2`),
KEY `fcode_country_idx` (`fcode`,`country`)
) ENGINE=InnoDB AUTO_INCREMENT=10346797 DEFAULT CHARSET=utf8 COLLATE=utf8_unicode_ci;
CREATE TABLE `alternatename` (
`alternatenameId` int(11) NOT NULL AUTO_INCREMENT,
`geonameid` int(11) NOT NULL,
`isoLanguage` varchar(7) COLLATE utf8_unicode_ci NOT NULL,
`alternateName` varchar(200) COLLATE utf8_unicode_ci NOT NULL,
`isPreferredName` tinyint(1) NOT NULL,
`isShortName` tinyint(1) NOT NULL,
`isColloquial` tinyint(1) NOT NULL,
`isHistoric` tinyint(1) NOT NULL,
PRIMARY KEY (`alternatenameId`),
KEY `IDX_8F82EED4E2097D` (`geonameid`),
KEY `idx_geoid_lang_pref` (`geonameid`,`isPreferredName`,`isoLanguage`),
CONSTRAINT `FK_8F82EED4E2097D` FOREIGN KEY (`geonameid`) REFERENCES `geoname` (`geonameid`)
) ENGINE=InnoDB AUTO_INCREMENT=10842837 DEFAULT CHARSET=utf8 COLLATE=utf8_unicode_ci;
mysql join execution-plan explain
mysql join execution-plan explain
edited Nov 17 '15 at 14:58
marcv
asked Nov 17 '15 at 11:00
marcvmarcv
1387
1387
bumped to the homepage by Community♦ 12 mins ago
This question has answers that may be good or bad; the system has marked it active so that they can be reviewed.
bumped to the homepage by Community♦ 12 mins ago
This question has answers that may be good or bad; the system has marked it active so that they can be reviewed.
1
I sure, correct answer for question - WHY? no body excluding few guys from Oracle/Percona/MariaDB who wrote query optimisation can not answer :) different versions of MySQL have different query optimisation algorythms also. if You want test it with other index - test it with FORCE index hint
– a_vlad
Nov 17 '15 at 11:32
I would suggest an index with different order:(isPreferredName, isoLanguage, geonameid)
– ypercubeᵀᴹ
Nov 17 '15 at 11:34
But you haven't provided with the exact version of MySQL (as @a_vlad pointed). And what are the tables sizes? How many rows does the query return? How much time does it need to run?
– ypercubeᵀᴹ
Nov 17 '15 at 11:37
Thanks for your comments, I updated my question with the data you asked.
– marcv
Nov 17 '15 at 11:55
1
I wonder why there is a question there. The query returns the answer (52 rows) in about a millisecond. Why would anyone care what indexes it uses?
– ypercubeᵀᴹ
Nov 17 '15 at 12:05
|
show 4 more comments
1
I sure, correct answer for question - WHY? no body excluding few guys from Oracle/Percona/MariaDB who wrote query optimisation can not answer :) different versions of MySQL have different query optimisation algorythms also. if You want test it with other index - test it with FORCE index hint
– a_vlad
Nov 17 '15 at 11:32
I would suggest an index with different order:(isPreferredName, isoLanguage, geonameid)
– ypercubeᵀᴹ
Nov 17 '15 at 11:34
But you haven't provided with the exact version of MySQL (as @a_vlad pointed). And what are the tables sizes? How many rows does the query return? How much time does it need to run?
– ypercubeᵀᴹ
Nov 17 '15 at 11:37
Thanks for your comments, I updated my question with the data you asked.
– marcv
Nov 17 '15 at 11:55
1
I wonder why there is a question there. The query returns the answer (52 rows) in about a millisecond. Why would anyone care what indexes it uses?
– ypercubeᵀᴹ
Nov 17 '15 at 12:05
1
1
I sure, correct answer for question - WHY? no body excluding few guys from Oracle/Percona/MariaDB who wrote query optimisation can not answer :) different versions of MySQL have different query optimisation algorythms also. if You want test it with other index - test it with FORCE index hint
– a_vlad
Nov 17 '15 at 11:32
I sure, correct answer for question - WHY? no body excluding few guys from Oracle/Percona/MariaDB who wrote query optimisation can not answer :) different versions of MySQL have different query optimisation algorythms also. if You want test it with other index - test it with FORCE index hint
– a_vlad
Nov 17 '15 at 11:32
I would suggest an index with different order:
(isPreferredName, isoLanguage, geonameid)
– ypercubeᵀᴹ
Nov 17 '15 at 11:34
I would suggest an index with different order:
(isPreferredName, isoLanguage, geonameid)
– ypercubeᵀᴹ
Nov 17 '15 at 11:34
But you haven't provided with the exact version of MySQL (as @a_vlad pointed). And what are the tables sizes? How many rows does the query return? How much time does it need to run?
– ypercubeᵀᴹ
Nov 17 '15 at 11:37
But you haven't provided with the exact version of MySQL (as @a_vlad pointed). And what are the tables sizes? How many rows does the query return? How much time does it need to run?
– ypercubeᵀᴹ
Nov 17 '15 at 11:37
Thanks for your comments, I updated my question with the data you asked.
– marcv
Nov 17 '15 at 11:55
Thanks for your comments, I updated my question with the data you asked.
– marcv
Nov 17 '15 at 11:55
1
1
I wonder why there is a question there. The query returns the answer (52 rows) in about a millisecond. Why would anyone care what indexes it uses?
– ypercubeᵀᴹ
Nov 17 '15 at 12:05
I wonder why there is a question there. The query returns the answer (52 rows) in about a millisecond. Why would anyone care what indexes it uses?
– ypercubeᵀᴹ
Nov 17 '15 at 12:05
|
show 4 more comments
3 Answers
3
active
oldest
votes
You do not use the isPreferredName
in your query. This must be a/the reason why the index is not used.
Also, the optimizer decides. It is not because you create an index that it will be used. All depends on the statistics for the table. How many rows? How many different unique values? What is the expected percentage of returned rows?
Sorry, I do use theisPreferredName
field in my query, my bad, I updated the code.
– marcv
Nov 17 '15 at 11:14
add a comment |
MySQL already can filter down to 1 row by using a different smaller index (only 4 bytes).
| 1 | SIMPLE | alternatename | ref | IDX_8F82EED4E2097D,idx_geoid_lang_pref | IDX_8F82EED4E2097D | 4 | acme_geonames.geoname.geonameid | 1 | Using where
So it doesn't need to use the bigger index.
Hope this answers your question.
I don't think this point helps any -- (1) drill down secondary BTree via geonameid, (2) drill down primary BTree to find the other 2 fields and check them. With the bigger index, "(2)" is avoided for the cases where they fail.
– Rick James
Dec 3 '15 at 2:47
add a comment |
Rearrange KEY idx_geoid_lang_pref
(geonameid
,isPreferredName
,isoLanguage
), to put geonameid
at the end.
In SELECT *
, how many of the fields of alternatename
do you need? If only one, do a subquery instead of a JOIN
.
I see no good reason to have alternatenameId
. And alternatename
.geonameid
is unique, correct? Hence, geonameid
could be the PRIMARY KEY
for that table.
My goal is not to correct the query to make it more efficient. What I want is understand the decision of the optimizer. And alternatename.geonameid is not unique, nope, as one geoname can have multiple alternatenames. It is a very badly designed schema but this is another topic.
– marcv
Dec 3 '15 at 22:05
Well, I don't understand why it picked the shorter index. It seems like a 'bug' in the optimizer. bugs.mysql.com might get to the optimizer guys and get the real answer. They are currently keen on "getting it right" in 5.7.
– Rick James
Dec 3 '15 at 23:28
add a comment |
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3 Answers
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You do not use the isPreferredName
in your query. This must be a/the reason why the index is not used.
Also, the optimizer decides. It is not because you create an index that it will be used. All depends on the statistics for the table. How many rows? How many different unique values? What is the expected percentage of returned rows?
Sorry, I do use theisPreferredName
field in my query, my bad, I updated the code.
– marcv
Nov 17 '15 at 11:14
add a comment |
You do not use the isPreferredName
in your query. This must be a/the reason why the index is not used.
Also, the optimizer decides. It is not because you create an index that it will be used. All depends on the statistics for the table. How many rows? How many different unique values? What is the expected percentage of returned rows?
Sorry, I do use theisPreferredName
field in my query, my bad, I updated the code.
– marcv
Nov 17 '15 at 11:14
add a comment |
You do not use the isPreferredName
in your query. This must be a/the reason why the index is not used.
Also, the optimizer decides. It is not because you create an index that it will be used. All depends on the statistics for the table. How many rows? How many different unique values? What is the expected percentage of returned rows?
You do not use the isPreferredName
in your query. This must be a/the reason why the index is not used.
Also, the optimizer decides. It is not because you create an index that it will be used. All depends on the statistics for the table. How many rows? How many different unique values? What is the expected percentage of returned rows?
answered Nov 17 '15 at 11:08
MarcoMarco
3,74231724
3,74231724
Sorry, I do use theisPreferredName
field in my query, my bad, I updated the code.
– marcv
Nov 17 '15 at 11:14
add a comment |
Sorry, I do use theisPreferredName
field in my query, my bad, I updated the code.
– marcv
Nov 17 '15 at 11:14
Sorry, I do use the
isPreferredName
field in my query, my bad, I updated the code.– marcv
Nov 17 '15 at 11:14
Sorry, I do use the
isPreferredName
field in my query, my bad, I updated the code.– marcv
Nov 17 '15 at 11:14
add a comment |
MySQL already can filter down to 1 row by using a different smaller index (only 4 bytes).
| 1 | SIMPLE | alternatename | ref | IDX_8F82EED4E2097D,idx_geoid_lang_pref | IDX_8F82EED4E2097D | 4 | acme_geonames.geoname.geonameid | 1 | Using where
So it doesn't need to use the bigger index.
Hope this answers your question.
I don't think this point helps any -- (1) drill down secondary BTree via geonameid, (2) drill down primary BTree to find the other 2 fields and check them. With the bigger index, "(2)" is avoided for the cases where they fail.
– Rick James
Dec 3 '15 at 2:47
add a comment |
MySQL already can filter down to 1 row by using a different smaller index (only 4 bytes).
| 1 | SIMPLE | alternatename | ref | IDX_8F82EED4E2097D,idx_geoid_lang_pref | IDX_8F82EED4E2097D | 4 | acme_geonames.geoname.geonameid | 1 | Using where
So it doesn't need to use the bigger index.
Hope this answers your question.
I don't think this point helps any -- (1) drill down secondary BTree via geonameid, (2) drill down primary BTree to find the other 2 fields and check them. With the bigger index, "(2)" is avoided for the cases where they fail.
– Rick James
Dec 3 '15 at 2:47
add a comment |
MySQL already can filter down to 1 row by using a different smaller index (only 4 bytes).
| 1 | SIMPLE | alternatename | ref | IDX_8F82EED4E2097D,idx_geoid_lang_pref | IDX_8F82EED4E2097D | 4 | acme_geonames.geoname.geonameid | 1 | Using where
So it doesn't need to use the bigger index.
Hope this answers your question.
MySQL already can filter down to 1 row by using a different smaller index (only 4 bytes).
| 1 | SIMPLE | alternatename | ref | IDX_8F82EED4E2097D,idx_geoid_lang_pref | IDX_8F82EED4E2097D | 4 | acme_geonames.geoname.geonameid | 1 | Using where
So it doesn't need to use the bigger index.
Hope this answers your question.
answered Nov 17 '15 at 17:26
Károly NagyKároly Nagy
2,5201611
2,5201611
I don't think this point helps any -- (1) drill down secondary BTree via geonameid, (2) drill down primary BTree to find the other 2 fields and check them. With the bigger index, "(2)" is avoided for the cases where they fail.
– Rick James
Dec 3 '15 at 2:47
add a comment |
I don't think this point helps any -- (1) drill down secondary BTree via geonameid, (2) drill down primary BTree to find the other 2 fields and check them. With the bigger index, "(2)" is avoided for the cases where they fail.
– Rick James
Dec 3 '15 at 2:47
I don't think this point helps any -- (1) drill down secondary BTree via geonameid, (2) drill down primary BTree to find the other 2 fields and check them. With the bigger index, "(2)" is avoided for the cases where they fail.
– Rick James
Dec 3 '15 at 2:47
I don't think this point helps any -- (1) drill down secondary BTree via geonameid, (2) drill down primary BTree to find the other 2 fields and check them. With the bigger index, "(2)" is avoided for the cases where they fail.
– Rick James
Dec 3 '15 at 2:47
add a comment |
Rearrange KEY idx_geoid_lang_pref
(geonameid
,isPreferredName
,isoLanguage
), to put geonameid
at the end.
In SELECT *
, how many of the fields of alternatename
do you need? If only one, do a subquery instead of a JOIN
.
I see no good reason to have alternatenameId
. And alternatename
.geonameid
is unique, correct? Hence, geonameid
could be the PRIMARY KEY
for that table.
My goal is not to correct the query to make it more efficient. What I want is understand the decision of the optimizer. And alternatename.geonameid is not unique, nope, as one geoname can have multiple alternatenames. It is a very badly designed schema but this is another topic.
– marcv
Dec 3 '15 at 22:05
Well, I don't understand why it picked the shorter index. It seems like a 'bug' in the optimizer. bugs.mysql.com might get to the optimizer guys and get the real answer. They are currently keen on "getting it right" in 5.7.
– Rick James
Dec 3 '15 at 23:28
add a comment |
Rearrange KEY idx_geoid_lang_pref
(geonameid
,isPreferredName
,isoLanguage
), to put geonameid
at the end.
In SELECT *
, how many of the fields of alternatename
do you need? If only one, do a subquery instead of a JOIN
.
I see no good reason to have alternatenameId
. And alternatename
.geonameid
is unique, correct? Hence, geonameid
could be the PRIMARY KEY
for that table.
My goal is not to correct the query to make it more efficient. What I want is understand the decision of the optimizer. And alternatename.geonameid is not unique, nope, as one geoname can have multiple alternatenames. It is a very badly designed schema but this is another topic.
– marcv
Dec 3 '15 at 22:05
Well, I don't understand why it picked the shorter index. It seems like a 'bug' in the optimizer. bugs.mysql.com might get to the optimizer guys and get the real answer. They are currently keen on "getting it right" in 5.7.
– Rick James
Dec 3 '15 at 23:28
add a comment |
Rearrange KEY idx_geoid_lang_pref
(geonameid
,isPreferredName
,isoLanguage
), to put geonameid
at the end.
In SELECT *
, how many of the fields of alternatename
do you need? If only one, do a subquery instead of a JOIN
.
I see no good reason to have alternatenameId
. And alternatename
.geonameid
is unique, correct? Hence, geonameid
could be the PRIMARY KEY
for that table.
Rearrange KEY idx_geoid_lang_pref
(geonameid
,isPreferredName
,isoLanguage
), to put geonameid
at the end.
In SELECT *
, how many of the fields of alternatename
do you need? If only one, do a subquery instead of a JOIN
.
I see no good reason to have alternatenameId
. And alternatename
.geonameid
is unique, correct? Hence, geonameid
could be the PRIMARY KEY
for that table.
answered Dec 3 '15 at 2:44
Rick JamesRick James
43.1k22259
43.1k22259
My goal is not to correct the query to make it more efficient. What I want is understand the decision of the optimizer. And alternatename.geonameid is not unique, nope, as one geoname can have multiple alternatenames. It is a very badly designed schema but this is another topic.
– marcv
Dec 3 '15 at 22:05
Well, I don't understand why it picked the shorter index. It seems like a 'bug' in the optimizer. bugs.mysql.com might get to the optimizer guys and get the real answer. They are currently keen on "getting it right" in 5.7.
– Rick James
Dec 3 '15 at 23:28
add a comment |
My goal is not to correct the query to make it more efficient. What I want is understand the decision of the optimizer. And alternatename.geonameid is not unique, nope, as one geoname can have multiple alternatenames. It is a very badly designed schema but this is another topic.
– marcv
Dec 3 '15 at 22:05
Well, I don't understand why it picked the shorter index. It seems like a 'bug' in the optimizer. bugs.mysql.com might get to the optimizer guys and get the real answer. They are currently keen on "getting it right" in 5.7.
– Rick James
Dec 3 '15 at 23:28
My goal is not to correct the query to make it more efficient. What I want is understand the decision of the optimizer. And alternatename.geonameid is not unique, nope, as one geoname can have multiple alternatenames. It is a very badly designed schema but this is another topic.
– marcv
Dec 3 '15 at 22:05
My goal is not to correct the query to make it more efficient. What I want is understand the decision of the optimizer. And alternatename.geonameid is not unique, nope, as one geoname can have multiple alternatenames. It is a very badly designed schema but this is another topic.
– marcv
Dec 3 '15 at 22:05
Well, I don't understand why it picked the shorter index. It seems like a 'bug' in the optimizer. bugs.mysql.com might get to the optimizer guys and get the real answer. They are currently keen on "getting it right" in 5.7.
– Rick James
Dec 3 '15 at 23:28
Well, I don't understand why it picked the shorter index. It seems like a 'bug' in the optimizer. bugs.mysql.com might get to the optimizer guys and get the real answer. They are currently keen on "getting it right" in 5.7.
– Rick James
Dec 3 '15 at 23:28
add a comment |
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1
I sure, correct answer for question - WHY? no body excluding few guys from Oracle/Percona/MariaDB who wrote query optimisation can not answer :) different versions of MySQL have different query optimisation algorythms also. if You want test it with other index - test it with FORCE index hint
– a_vlad
Nov 17 '15 at 11:32
I would suggest an index with different order:
(isPreferredName, isoLanguage, geonameid)
– ypercubeᵀᴹ
Nov 17 '15 at 11:34
But you haven't provided with the exact version of MySQL (as @a_vlad pointed). And what are the tables sizes? How many rows does the query return? How much time does it need to run?
– ypercubeᵀᴹ
Nov 17 '15 at 11:37
Thanks for your comments, I updated my question with the data you asked.
– marcv
Nov 17 '15 at 11:55
1
I wonder why there is a question there. The query returns the answer (52 rows) in about a millisecond. Why would anyone care what indexes it uses?
– ypercubeᵀᴹ
Nov 17 '15 at 12:05