Why am I getting table does not exist error?












0















so I'm trying to creating a database table using pg admin. I created a table in pg admin and then I was supposed to run the table using putty. But when I run it it says error table does not exist. The table does exist though so I don't know why I'm getting that error!



--Dropping tables clear out any existing data
DROP TABLE IF EXISTS automobiles;

CREATE TABLE automobiles(
id INTEGER PRIMARY KEY,
make VARCHAR(15)NOT NULL,
model VARCHAR(20)NOT NULL,
year INTEGER NOT NULL,
owner CHAR(25) NOT NULL,
msrp DECIMAL NOT NULL,
purchase_date DATE NOT NULL
);



INSERT INTO automobiles(id, make, model, year, owner, msrp, purchase_date) VALUES(
1,
'Ferarri',
'F40',
'1987',
'',
'1690000',
'3/12/2019');
INSERT INTO automobiles(id, make, model, year,owner, msrp, purchase_date)VALUES(
2,
'Tundra',
'4X2',
'2019',
'',
'39625',
'3/12/2019');
INSERT INTO automobiles(id, make, model, year,owner, msrp, purchase_date) VALUES(
3,
'Mercedes-Benz',
'AMG GT',
'2014',
'',
'145000',
'3/12/2019');
INSERT INTO automobiles(id, make, model, year,owner, msrp, purchase_date)VALUES(
4,
'Chrysler',
'300',
'2004',
'',
'800',
'3/12/2019');
INSERT INTO automobiles(id, make, model, year,owner, msrp, purchase_date) VALUES(
5,
'Jeep',
'Wrangler',
'2019',
'',
'33695',
'3/12/2019');

SELECT make, model, year, msrp FROM automobiles ORDER BY year ASC;

UPDATE automobiles
SET owner = 'Deanna Slotegraaf'
WHERE make = 'ferarri';

DELETE FROM automobiles WHERE make = 'Chrysler';


This is the full set of code that I have.



Thanks...









share







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    0















    so I'm trying to creating a database table using pg admin. I created a table in pg admin and then I was supposed to run the table using putty. But when I run it it says error table does not exist. The table does exist though so I don't know why I'm getting that error!



    --Dropping tables clear out any existing data
    DROP TABLE IF EXISTS automobiles;

    CREATE TABLE automobiles(
    id INTEGER PRIMARY KEY,
    make VARCHAR(15)NOT NULL,
    model VARCHAR(20)NOT NULL,
    year INTEGER NOT NULL,
    owner CHAR(25) NOT NULL,
    msrp DECIMAL NOT NULL,
    purchase_date DATE NOT NULL
    );



    INSERT INTO automobiles(id, make, model, year, owner, msrp, purchase_date) VALUES(
    1,
    'Ferarri',
    'F40',
    '1987',
    '',
    '1690000',
    '3/12/2019');
    INSERT INTO automobiles(id, make, model, year,owner, msrp, purchase_date)VALUES(
    2,
    'Tundra',
    '4X2',
    '2019',
    '',
    '39625',
    '3/12/2019');
    INSERT INTO automobiles(id, make, model, year,owner, msrp, purchase_date) VALUES(
    3,
    'Mercedes-Benz',
    'AMG GT',
    '2014',
    '',
    '145000',
    '3/12/2019');
    INSERT INTO automobiles(id, make, model, year,owner, msrp, purchase_date)VALUES(
    4,
    'Chrysler',
    '300',
    '2004',
    '',
    '800',
    '3/12/2019');
    INSERT INTO automobiles(id, make, model, year,owner, msrp, purchase_date) VALUES(
    5,
    'Jeep',
    'Wrangler',
    '2019',
    '',
    '33695',
    '3/12/2019');

    SELECT make, model, year, msrp FROM automobiles ORDER BY year ASC;

    UPDATE automobiles
    SET owner = 'Deanna Slotegraaf'
    WHERE make = 'ferarri';

    DELETE FROM automobiles WHERE make = 'Chrysler';


    This is the full set of code that I have.



    Thanks...









    share







    New contributor




    Dee Slotegraaf is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.























      0












      0








      0








      so I'm trying to creating a database table using pg admin. I created a table in pg admin and then I was supposed to run the table using putty. But when I run it it says error table does not exist. The table does exist though so I don't know why I'm getting that error!



      --Dropping tables clear out any existing data
      DROP TABLE IF EXISTS automobiles;

      CREATE TABLE automobiles(
      id INTEGER PRIMARY KEY,
      make VARCHAR(15)NOT NULL,
      model VARCHAR(20)NOT NULL,
      year INTEGER NOT NULL,
      owner CHAR(25) NOT NULL,
      msrp DECIMAL NOT NULL,
      purchase_date DATE NOT NULL
      );



      INSERT INTO automobiles(id, make, model, year, owner, msrp, purchase_date) VALUES(
      1,
      'Ferarri',
      'F40',
      '1987',
      '',
      '1690000',
      '3/12/2019');
      INSERT INTO automobiles(id, make, model, year,owner, msrp, purchase_date)VALUES(
      2,
      'Tundra',
      '4X2',
      '2019',
      '',
      '39625',
      '3/12/2019');
      INSERT INTO automobiles(id, make, model, year,owner, msrp, purchase_date) VALUES(
      3,
      'Mercedes-Benz',
      'AMG GT',
      '2014',
      '',
      '145000',
      '3/12/2019');
      INSERT INTO automobiles(id, make, model, year,owner, msrp, purchase_date)VALUES(
      4,
      'Chrysler',
      '300',
      '2004',
      '',
      '800',
      '3/12/2019');
      INSERT INTO automobiles(id, make, model, year,owner, msrp, purchase_date) VALUES(
      5,
      'Jeep',
      'Wrangler',
      '2019',
      '',
      '33695',
      '3/12/2019');

      SELECT make, model, year, msrp FROM automobiles ORDER BY year ASC;

      UPDATE automobiles
      SET owner = 'Deanna Slotegraaf'
      WHERE make = 'ferarri';

      DELETE FROM automobiles WHERE make = 'Chrysler';


      This is the full set of code that I have.



      Thanks...









      share







      New contributor




      Dee Slotegraaf is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.












      so I'm trying to creating a database table using pg admin. I created a table in pg admin and then I was supposed to run the table using putty. But when I run it it says error table does not exist. The table does exist though so I don't know why I'm getting that error!



      --Dropping tables clear out any existing data
      DROP TABLE IF EXISTS automobiles;

      CREATE TABLE automobiles(
      id INTEGER PRIMARY KEY,
      make VARCHAR(15)NOT NULL,
      model VARCHAR(20)NOT NULL,
      year INTEGER NOT NULL,
      owner CHAR(25) NOT NULL,
      msrp DECIMAL NOT NULL,
      purchase_date DATE NOT NULL
      );



      INSERT INTO automobiles(id, make, model, year, owner, msrp, purchase_date) VALUES(
      1,
      'Ferarri',
      'F40',
      '1987',
      '',
      '1690000',
      '3/12/2019');
      INSERT INTO automobiles(id, make, model, year,owner, msrp, purchase_date)VALUES(
      2,
      'Tundra',
      '4X2',
      '2019',
      '',
      '39625',
      '3/12/2019');
      INSERT INTO automobiles(id, make, model, year,owner, msrp, purchase_date) VALUES(
      3,
      'Mercedes-Benz',
      'AMG GT',
      '2014',
      '',
      '145000',
      '3/12/2019');
      INSERT INTO automobiles(id, make, model, year,owner, msrp, purchase_date)VALUES(
      4,
      'Chrysler',
      '300',
      '2004',
      '',
      '800',
      '3/12/2019');
      INSERT INTO automobiles(id, make, model, year,owner, msrp, purchase_date) VALUES(
      5,
      'Jeep',
      'Wrangler',
      '2019',
      '',
      '33695',
      '3/12/2019');

      SELECT make, model, year, msrp FROM automobiles ORDER BY year ASC;

      UPDATE automobiles
      SET owner = 'Deanna Slotegraaf'
      WHERE make = 'ferarri';

      DELETE FROM automobiles WHERE make = 'Chrysler';


      This is the full set of code that I have.



      Thanks...







      postgresql pgadmin





      share







      New contributor




      Dee Slotegraaf is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.










      share







      New contributor




      Dee Slotegraaf is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.








      share



      share






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      Check out our Code of Conduct.









      asked 2 mins ago









      Dee SlotegraafDee Slotegraaf

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      New contributor





      Dee Slotegraaf is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.






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