linux find command for filenames without extension for unknown extensions












2















I like using the following command to print file names but it prints them with extensions.



find . -type f -printf '%fn'


In my directory, there are many files with different extensions. I tried adding --ignore='*.*' both before and after -printf, but it didn't work.
example; I have files myfile1.txt, myfile2.mp3, etc. I need it prints myfile1, myfile2, etc.
How would I do this?










share|improve this question





























    2















    I like using the following command to print file names but it prints them with extensions.



    find . -type f -printf '%fn'


    In my directory, there are many files with different extensions. I tried adding --ignore='*.*' both before and after -printf, but it didn't work.
    example; I have files myfile1.txt, myfile2.mp3, etc. I need it prints myfile1, myfile2, etc.
    How would I do this?










    share|improve this question



























      2












      2








      2








      I like using the following command to print file names but it prints them with extensions.



      find . -type f -printf '%fn'


      In my directory, there are many files with different extensions. I tried adding --ignore='*.*' both before and after -printf, but it didn't work.
      example; I have files myfile1.txt, myfile2.mp3, etc. I need it prints myfile1, myfile2, etc.
      How would I do this?










      share|improve this question
















      I like using the following command to print file names but it prints them with extensions.



      find . -type f -printf '%fn'


      In my directory, there are many files with different extensions. I tried adding --ignore='*.*' both before and after -printf, but it didn't work.
      example; I have files myfile1.txt, myfile2.mp3, etc. I need it prints myfile1, myfile2, etc.
      How would I do this?







      find filenames






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited 16 mins ago







      kutlus

















      asked 58 mins ago









      kutluskutlus

      415




      415






















          4 Answers
          4






          active

          oldest

          votes


















          2














          If I understand you correctly (I didn't, see second part of the answer), you want to avoid listing filenames that contain a dot character.



          This will do that:



          find . -type f ! -name '*.*'


          The filename globbing pattern *.* would match any filename containing at least one dot. The preceding ! negates the sense of the match, which means that the pathnames that gets through to the end will be those of files that have no dots in their names. In really ancient shells, you may want to escape the ! as ! (or update your Unix installation). The lone ! won't invoke bash's history expansion facility.



          To print only the filename component of the found pathname, with GNU find:



          find . -type f ! -name '*.*' -printf '%fn'


          With standard find (or GNU find for that matter):



          find . -type f ! -name '*.*' -exec basename {} ;


          Before using this in a command substitution in a loop, see "Why is looping over find's output bad practice?".





          To list all filenames, and at the same time remove everything after the last dot in the name ("remove the extension"), you may use



          find . -type f -exec sh -c '
          for pathname do
          pathname=$( basename "$pathname" )
          printf "%sn" "${pathname%.*}"
          done' sh {} +


          This would send all found pathnames of all files to a short shell loop. The loop would take each pathname and call basename on it to extract the filename component of the pathname, and then print the resulting string with everything after the last dot removed.



          The parameter expansion ${pathname%.*} means "remove the shortest string matching .* (a literal dot followed by arbitrary text) from the end of the value of $pathname". It would have the effect of removing a filename suffix after the last dot in the filename.



          For more info about find ... -exec ... {} +, see e.g. "Understanding the -exec option of `find`".






          share|improve this answer


























          • Thanks for your help, I have tried all three, but they don't print anything. Am I missing something, on the same terminal, in the same directory find . -type f -printf '%fn' works but as I asked in the question I need them without extensions.

            – kutlus
            26 mins ago











          • @kutlus In that case, I (and the others) may have misunderstood your question. Do you want to remove everything after the last dot in the filename?

            – Kusalananda
            24 mins ago











          • I just want the file name, example; some files are myfile1.txt, myfile2.mp3, i want it prints myfile1, myfile2. sorry if my questions wasn`t clear, thanks

            – kutlus
            21 mins ago











          • @kutlus See updated answer.

            – Kusalananda
            17 mins ago











          • This worked, many thanks!

            – kutlus
            14 mins ago



















          1














          In Linux, there is no such thing as a file extension. A . in a file name has no significance whatsoever (notwithstanding that a . as the first character in a filename identifies it as a hidden file).



          Also, checking the manual page for find on my system shows no --ignore option.



          That said, if you want to ignore any files with a . in their name, you can use find's -not operator:



          find -type f -not -name '*.*' -print





          share|improve this answer
























          • thanks but this doesn`t print anything.

            – kutlus
            30 mins ago



















          1














          try



          find . -type f ! -name '*.*' -print


          where





          • ! : not (! must be escaped)


          • name '*.*' : filename with extension






          share|improve this answer
























          • arg, not fast enough !!

            – Archemar
            51 mins ago











          • Having to escape ! is why I usually suggest using -not.

            – DopeGhoti
            51 mins ago











          • well it work w/o escape, I've been escaping it ever since SunOS 3.X... sight.

            – Archemar
            50 mins ago











          • thanks but this doesn`t print anything.

            – kutlus
            31 mins ago



















          1














          As other's have pointed out, "extensions" don't really mean anything to Unix systems. But we can remove them from a listing with a simple sed command.



          e.g.



          find * -type f -print | sed 's/.[^.]*$//'


          If there are directories and you don't want them to be shown in the listing then



          find * -type f -printf "%fn" | sed 's/.[^.]*$//'


          For a single directory we can just use ls instead of find



          ls | sed 's/.[^.]*$//'





          share|improve this answer























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            4 Answers
            4






            active

            oldest

            votes








            4 Answers
            4






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes









            2














            If I understand you correctly (I didn't, see second part of the answer), you want to avoid listing filenames that contain a dot character.



            This will do that:



            find . -type f ! -name '*.*'


            The filename globbing pattern *.* would match any filename containing at least one dot. The preceding ! negates the sense of the match, which means that the pathnames that gets through to the end will be those of files that have no dots in their names. In really ancient shells, you may want to escape the ! as ! (or update your Unix installation). The lone ! won't invoke bash's history expansion facility.



            To print only the filename component of the found pathname, with GNU find:



            find . -type f ! -name '*.*' -printf '%fn'


            With standard find (or GNU find for that matter):



            find . -type f ! -name '*.*' -exec basename {} ;


            Before using this in a command substitution in a loop, see "Why is looping over find's output bad practice?".





            To list all filenames, and at the same time remove everything after the last dot in the name ("remove the extension"), you may use



            find . -type f -exec sh -c '
            for pathname do
            pathname=$( basename "$pathname" )
            printf "%sn" "${pathname%.*}"
            done' sh {} +


            This would send all found pathnames of all files to a short shell loop. The loop would take each pathname and call basename on it to extract the filename component of the pathname, and then print the resulting string with everything after the last dot removed.



            The parameter expansion ${pathname%.*} means "remove the shortest string matching .* (a literal dot followed by arbitrary text) from the end of the value of $pathname". It would have the effect of removing a filename suffix after the last dot in the filename.



            For more info about find ... -exec ... {} +, see e.g. "Understanding the -exec option of `find`".






            share|improve this answer


























            • Thanks for your help, I have tried all three, but they don't print anything. Am I missing something, on the same terminal, in the same directory find . -type f -printf '%fn' works but as I asked in the question I need them without extensions.

              – kutlus
              26 mins ago











            • @kutlus In that case, I (and the others) may have misunderstood your question. Do you want to remove everything after the last dot in the filename?

              – Kusalananda
              24 mins ago











            • I just want the file name, example; some files are myfile1.txt, myfile2.mp3, i want it prints myfile1, myfile2. sorry if my questions wasn`t clear, thanks

              – kutlus
              21 mins ago











            • @kutlus See updated answer.

              – Kusalananda
              17 mins ago











            • This worked, many thanks!

              – kutlus
              14 mins ago
















            2














            If I understand you correctly (I didn't, see second part of the answer), you want to avoid listing filenames that contain a dot character.



            This will do that:



            find . -type f ! -name '*.*'


            The filename globbing pattern *.* would match any filename containing at least one dot. The preceding ! negates the sense of the match, which means that the pathnames that gets through to the end will be those of files that have no dots in their names. In really ancient shells, you may want to escape the ! as ! (or update your Unix installation). The lone ! won't invoke bash's history expansion facility.



            To print only the filename component of the found pathname, with GNU find:



            find . -type f ! -name '*.*' -printf '%fn'


            With standard find (or GNU find for that matter):



            find . -type f ! -name '*.*' -exec basename {} ;


            Before using this in a command substitution in a loop, see "Why is looping over find's output bad practice?".





            To list all filenames, and at the same time remove everything after the last dot in the name ("remove the extension"), you may use



            find . -type f -exec sh -c '
            for pathname do
            pathname=$( basename "$pathname" )
            printf "%sn" "${pathname%.*}"
            done' sh {} +


            This would send all found pathnames of all files to a short shell loop. The loop would take each pathname and call basename on it to extract the filename component of the pathname, and then print the resulting string with everything after the last dot removed.



            The parameter expansion ${pathname%.*} means "remove the shortest string matching .* (a literal dot followed by arbitrary text) from the end of the value of $pathname". It would have the effect of removing a filename suffix after the last dot in the filename.



            For more info about find ... -exec ... {} +, see e.g. "Understanding the -exec option of `find`".






            share|improve this answer


























            • Thanks for your help, I have tried all three, but they don't print anything. Am I missing something, on the same terminal, in the same directory find . -type f -printf '%fn' works but as I asked in the question I need them without extensions.

              – kutlus
              26 mins ago











            • @kutlus In that case, I (and the others) may have misunderstood your question. Do you want to remove everything after the last dot in the filename?

              – Kusalananda
              24 mins ago











            • I just want the file name, example; some files are myfile1.txt, myfile2.mp3, i want it prints myfile1, myfile2. sorry if my questions wasn`t clear, thanks

              – kutlus
              21 mins ago











            • @kutlus See updated answer.

              – Kusalananda
              17 mins ago











            • This worked, many thanks!

              – kutlus
              14 mins ago














            2












            2








            2







            If I understand you correctly (I didn't, see second part of the answer), you want to avoid listing filenames that contain a dot character.



            This will do that:



            find . -type f ! -name '*.*'


            The filename globbing pattern *.* would match any filename containing at least one dot. The preceding ! negates the sense of the match, which means that the pathnames that gets through to the end will be those of files that have no dots in their names. In really ancient shells, you may want to escape the ! as ! (or update your Unix installation). The lone ! won't invoke bash's history expansion facility.



            To print only the filename component of the found pathname, with GNU find:



            find . -type f ! -name '*.*' -printf '%fn'


            With standard find (or GNU find for that matter):



            find . -type f ! -name '*.*' -exec basename {} ;


            Before using this in a command substitution in a loop, see "Why is looping over find's output bad practice?".





            To list all filenames, and at the same time remove everything after the last dot in the name ("remove the extension"), you may use



            find . -type f -exec sh -c '
            for pathname do
            pathname=$( basename "$pathname" )
            printf "%sn" "${pathname%.*}"
            done' sh {} +


            This would send all found pathnames of all files to a short shell loop. The loop would take each pathname and call basename on it to extract the filename component of the pathname, and then print the resulting string with everything after the last dot removed.



            The parameter expansion ${pathname%.*} means "remove the shortest string matching .* (a literal dot followed by arbitrary text) from the end of the value of $pathname". It would have the effect of removing a filename suffix after the last dot in the filename.



            For more info about find ... -exec ... {} +, see e.g. "Understanding the -exec option of `find`".






            share|improve this answer















            If I understand you correctly (I didn't, see second part of the answer), you want to avoid listing filenames that contain a dot character.



            This will do that:



            find . -type f ! -name '*.*'


            The filename globbing pattern *.* would match any filename containing at least one dot. The preceding ! negates the sense of the match, which means that the pathnames that gets through to the end will be those of files that have no dots in their names. In really ancient shells, you may want to escape the ! as ! (or update your Unix installation). The lone ! won't invoke bash's history expansion facility.



            To print only the filename component of the found pathname, with GNU find:



            find . -type f ! -name '*.*' -printf '%fn'


            With standard find (or GNU find for that matter):



            find . -type f ! -name '*.*' -exec basename {} ;


            Before using this in a command substitution in a loop, see "Why is looping over find's output bad practice?".





            To list all filenames, and at the same time remove everything after the last dot in the name ("remove the extension"), you may use



            find . -type f -exec sh -c '
            for pathname do
            pathname=$( basename "$pathname" )
            printf "%sn" "${pathname%.*}"
            done' sh {} +


            This would send all found pathnames of all files to a short shell loop. The loop would take each pathname and call basename on it to extract the filename component of the pathname, and then print the resulting string with everything after the last dot removed.



            The parameter expansion ${pathname%.*} means "remove the shortest string matching .* (a literal dot followed by arbitrary text) from the end of the value of $pathname". It would have the effect of removing a filename suffix after the last dot in the filename.



            For more info about find ... -exec ... {} +, see e.g. "Understanding the -exec option of `find`".







            share|improve this answer














            share|improve this answer



            share|improve this answer








            edited 14 mins ago

























            answered 53 mins ago









            KusalanandaKusalananda

            126k16239391




            126k16239391













            • Thanks for your help, I have tried all three, but they don't print anything. Am I missing something, on the same terminal, in the same directory find . -type f -printf '%fn' works but as I asked in the question I need them without extensions.

              – kutlus
              26 mins ago











            • @kutlus In that case, I (and the others) may have misunderstood your question. Do you want to remove everything after the last dot in the filename?

              – Kusalananda
              24 mins ago











            • I just want the file name, example; some files are myfile1.txt, myfile2.mp3, i want it prints myfile1, myfile2. sorry if my questions wasn`t clear, thanks

              – kutlus
              21 mins ago











            • @kutlus See updated answer.

              – Kusalananda
              17 mins ago











            • This worked, many thanks!

              – kutlus
              14 mins ago



















            • Thanks for your help, I have tried all three, but they don't print anything. Am I missing something, on the same terminal, in the same directory find . -type f -printf '%fn' works but as I asked in the question I need them without extensions.

              – kutlus
              26 mins ago











            • @kutlus In that case, I (and the others) may have misunderstood your question. Do you want to remove everything after the last dot in the filename?

              – Kusalananda
              24 mins ago











            • I just want the file name, example; some files are myfile1.txt, myfile2.mp3, i want it prints myfile1, myfile2. sorry if my questions wasn`t clear, thanks

              – kutlus
              21 mins ago











            • @kutlus See updated answer.

              – Kusalananda
              17 mins ago











            • This worked, many thanks!

              – kutlus
              14 mins ago

















            Thanks for your help, I have tried all three, but they don't print anything. Am I missing something, on the same terminal, in the same directory find . -type f -printf '%fn' works but as I asked in the question I need them without extensions.

            – kutlus
            26 mins ago





            Thanks for your help, I have tried all three, but they don't print anything. Am I missing something, on the same terminal, in the same directory find . -type f -printf '%fn' works but as I asked in the question I need them without extensions.

            – kutlus
            26 mins ago













            @kutlus In that case, I (and the others) may have misunderstood your question. Do you want to remove everything after the last dot in the filename?

            – Kusalananda
            24 mins ago





            @kutlus In that case, I (and the others) may have misunderstood your question. Do you want to remove everything after the last dot in the filename?

            – Kusalananda
            24 mins ago













            I just want the file name, example; some files are myfile1.txt, myfile2.mp3, i want it prints myfile1, myfile2. sorry if my questions wasn`t clear, thanks

            – kutlus
            21 mins ago





            I just want the file name, example; some files are myfile1.txt, myfile2.mp3, i want it prints myfile1, myfile2. sorry if my questions wasn`t clear, thanks

            – kutlus
            21 mins ago













            @kutlus See updated answer.

            – Kusalananda
            17 mins ago





            @kutlus See updated answer.

            – Kusalananda
            17 mins ago













            This worked, many thanks!

            – kutlus
            14 mins ago





            This worked, many thanks!

            – kutlus
            14 mins ago













            1














            In Linux, there is no such thing as a file extension. A . in a file name has no significance whatsoever (notwithstanding that a . as the first character in a filename identifies it as a hidden file).



            Also, checking the manual page for find on my system shows no --ignore option.



            That said, if you want to ignore any files with a . in their name, you can use find's -not operator:



            find -type f -not -name '*.*' -print





            share|improve this answer
























            • thanks but this doesn`t print anything.

              – kutlus
              30 mins ago
















            1














            In Linux, there is no such thing as a file extension. A . in a file name has no significance whatsoever (notwithstanding that a . as the first character in a filename identifies it as a hidden file).



            Also, checking the manual page for find on my system shows no --ignore option.



            That said, if you want to ignore any files with a . in their name, you can use find's -not operator:



            find -type f -not -name '*.*' -print





            share|improve this answer
























            • thanks but this doesn`t print anything.

              – kutlus
              30 mins ago














            1












            1








            1







            In Linux, there is no such thing as a file extension. A . in a file name has no significance whatsoever (notwithstanding that a . as the first character in a filename identifies it as a hidden file).



            Also, checking the manual page for find on my system shows no --ignore option.



            That said, if you want to ignore any files with a . in their name, you can use find's -not operator:



            find -type f -not -name '*.*' -print





            share|improve this answer













            In Linux, there is no such thing as a file extension. A . in a file name has no significance whatsoever (notwithstanding that a . as the first character in a filename identifies it as a hidden file).



            Also, checking the manual page for find on my system shows no --ignore option.



            That said, if you want to ignore any files with a . in their name, you can use find's -not operator:



            find -type f -not -name '*.*' -print






            share|improve this answer












            share|improve this answer



            share|improve this answer










            answered 52 mins ago









            DopeGhotiDopeGhoti

            44.3k55684




            44.3k55684













            • thanks but this doesn`t print anything.

              – kutlus
              30 mins ago



















            • thanks but this doesn`t print anything.

              – kutlus
              30 mins ago

















            thanks but this doesn`t print anything.

            – kutlus
            30 mins ago





            thanks but this doesn`t print anything.

            – kutlus
            30 mins ago











            1














            try



            find . -type f ! -name '*.*' -print


            where





            • ! : not (! must be escaped)


            • name '*.*' : filename with extension






            share|improve this answer
























            • arg, not fast enough !!

              – Archemar
              51 mins ago











            • Having to escape ! is why I usually suggest using -not.

              – DopeGhoti
              51 mins ago











            • well it work w/o escape, I've been escaping it ever since SunOS 3.X... sight.

              – Archemar
              50 mins ago











            • thanks but this doesn`t print anything.

              – kutlus
              31 mins ago
















            1














            try



            find . -type f ! -name '*.*' -print


            where





            • ! : not (! must be escaped)


            • name '*.*' : filename with extension






            share|improve this answer
























            • arg, not fast enough !!

              – Archemar
              51 mins ago











            • Having to escape ! is why I usually suggest using -not.

              – DopeGhoti
              51 mins ago











            • well it work w/o escape, I've been escaping it ever since SunOS 3.X... sight.

              – Archemar
              50 mins ago











            • thanks but this doesn`t print anything.

              – kutlus
              31 mins ago














            1












            1








            1







            try



            find . -type f ! -name '*.*' -print


            where





            • ! : not (! must be escaped)


            • name '*.*' : filename with extension






            share|improve this answer













            try



            find . -type f ! -name '*.*' -print


            where





            • ! : not (! must be escaped)


            • name '*.*' : filename with extension







            share|improve this answer












            share|improve this answer



            share|improve this answer










            answered 52 mins ago









            ArchemarArchemar

            19.9k93670




            19.9k93670













            • arg, not fast enough !!

              – Archemar
              51 mins ago











            • Having to escape ! is why I usually suggest using -not.

              – DopeGhoti
              51 mins ago











            • well it work w/o escape, I've been escaping it ever since SunOS 3.X... sight.

              – Archemar
              50 mins ago











            • thanks but this doesn`t print anything.

              – kutlus
              31 mins ago



















            • arg, not fast enough !!

              – Archemar
              51 mins ago











            • Having to escape ! is why I usually suggest using -not.

              – DopeGhoti
              51 mins ago











            • well it work w/o escape, I've been escaping it ever since SunOS 3.X... sight.

              – Archemar
              50 mins ago











            • thanks but this doesn`t print anything.

              – kutlus
              31 mins ago

















            arg, not fast enough !!

            – Archemar
            51 mins ago





            arg, not fast enough !!

            – Archemar
            51 mins ago













            Having to escape ! is why I usually suggest using -not.

            – DopeGhoti
            51 mins ago





            Having to escape ! is why I usually suggest using -not.

            – DopeGhoti
            51 mins ago













            well it work w/o escape, I've been escaping it ever since SunOS 3.X... sight.

            – Archemar
            50 mins ago





            well it work w/o escape, I've been escaping it ever since SunOS 3.X... sight.

            – Archemar
            50 mins ago













            thanks but this doesn`t print anything.

            – kutlus
            31 mins ago





            thanks but this doesn`t print anything.

            – kutlus
            31 mins ago











            1














            As other's have pointed out, "extensions" don't really mean anything to Unix systems. But we can remove them from a listing with a simple sed command.



            e.g.



            find * -type f -print | sed 's/.[^.]*$//'


            If there are directories and you don't want them to be shown in the listing then



            find * -type f -printf "%fn" | sed 's/.[^.]*$//'


            For a single directory we can just use ls instead of find



            ls | sed 's/.[^.]*$//'





            share|improve this answer




























              1














              As other's have pointed out, "extensions" don't really mean anything to Unix systems. But we can remove them from a listing with a simple sed command.



              e.g.



              find * -type f -print | sed 's/.[^.]*$//'


              If there are directories and you don't want them to be shown in the listing then



              find * -type f -printf "%fn" | sed 's/.[^.]*$//'


              For a single directory we can just use ls instead of find



              ls | sed 's/.[^.]*$//'





              share|improve this answer


























                1












                1








                1







                As other's have pointed out, "extensions" don't really mean anything to Unix systems. But we can remove them from a listing with a simple sed command.



                e.g.



                find * -type f -print | sed 's/.[^.]*$//'


                If there are directories and you don't want them to be shown in the listing then



                find * -type f -printf "%fn" | sed 's/.[^.]*$//'


                For a single directory we can just use ls instead of find



                ls | sed 's/.[^.]*$//'





                share|improve this answer













                As other's have pointed out, "extensions" don't really mean anything to Unix systems. But we can remove them from a listing with a simple sed command.



                e.g.



                find * -type f -print | sed 's/.[^.]*$//'


                If there are directories and you don't want them to be shown in the listing then



                find * -type f -printf "%fn" | sed 's/.[^.]*$//'


                For a single directory we can just use ls instead of find



                ls | sed 's/.[^.]*$//'






                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered 12 mins ago









                Stephen HarrisStephen Harris

                25.5k24477




                25.5k24477






























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