linux find command for filenames without extension for unknown extensions
I like using the following command to print file names but it prints them with extensions.
find . -type f -printf '%fn'
In my directory, there are many files with different extensions. I tried adding --ignore='*.*'
both before and after -printf
, but it didn't work.
example; I have files myfile1.txt, myfile2.mp3, etc. I need it prints myfile1, myfile2, etc.
How would I do this?
find filenames
add a comment |
I like using the following command to print file names but it prints them with extensions.
find . -type f -printf '%fn'
In my directory, there are many files with different extensions. I tried adding --ignore='*.*'
both before and after -printf
, but it didn't work.
example; I have files myfile1.txt, myfile2.mp3, etc. I need it prints myfile1, myfile2, etc.
How would I do this?
find filenames
add a comment |
I like using the following command to print file names but it prints them with extensions.
find . -type f -printf '%fn'
In my directory, there are many files with different extensions. I tried adding --ignore='*.*'
both before and after -printf
, but it didn't work.
example; I have files myfile1.txt, myfile2.mp3, etc. I need it prints myfile1, myfile2, etc.
How would I do this?
find filenames
I like using the following command to print file names but it prints them with extensions.
find . -type f -printf '%fn'
In my directory, there are many files with different extensions. I tried adding --ignore='*.*'
both before and after -printf
, but it didn't work.
example; I have files myfile1.txt, myfile2.mp3, etc. I need it prints myfile1, myfile2, etc.
How would I do this?
find filenames
find filenames
edited 16 mins ago
kutlus
asked 58 mins ago
kutluskutlus
415
415
add a comment |
add a comment |
4 Answers
4
active
oldest
votes
If I understand you correctly (I didn't, see second part of the answer), you want to avoid listing filenames that contain a dot character.
This will do that:
find . -type f ! -name '*.*'
The filename globbing pattern *.*
would match any filename containing at least one dot. The preceding !
negates the sense of the match, which means that the pathnames that gets through to the end will be those of files that have no dots in their names. In really ancient shells, you may want to escape the !
as !
(or update your Unix installation). The lone !
won't invoke bash
's history expansion facility.
To print only the filename component of the found pathname, with GNU find
:
find . -type f ! -name '*.*' -printf '%fn'
With standard find
(or GNU find
for that matter):
find . -type f ! -name '*.*' -exec basename {} ;
Before using this in a command substitution in a loop, see "Why is looping over find's output bad practice?".
To list all filenames, and at the same time remove everything after the last dot in the name ("remove the extension"), you may use
find . -type f -exec sh -c '
for pathname do
pathname=$( basename "$pathname" )
printf "%sn" "${pathname%.*}"
done' sh {} +
This would send all found pathnames of all files to a short shell loop. The loop would take each pathname and call basename
on it to extract the filename component of the pathname, and then print the resulting string with everything after the last dot removed.
The parameter expansion ${pathname%.*}
means "remove the shortest string matching .*
(a literal dot followed by arbitrary text) from the end of the value of $pathname
". It would have the effect of removing a filename suffix after the last dot in the filename.
For more info about find ... -exec ... {} +
, see e.g. "Understanding the -exec option of `find`".
Thanks for your help, I have tried all three, but they don't print anything. Am I missing something, on the same terminal, in the same directory find . -type f -printf '%fn' works but as I asked in the question I need them without extensions.
– kutlus
26 mins ago
@kutlus In that case, I (and the others) may have misunderstood your question. Do you want to remove everything after the last dot in the filename?
– Kusalananda
24 mins ago
I just want the file name, example; some files are myfile1.txt, myfile2.mp3, i want it prints myfile1, myfile2. sorry if my questions wasn`t clear, thanks
– kutlus
21 mins ago
@kutlus See updated answer.
– Kusalananda
17 mins ago
This worked, many thanks!
– kutlus
14 mins ago
add a comment |
In Linux, there is no such thing as a file extension. A .
in a file name has no significance whatsoever (notwithstanding that a .
as the first character in a filename identifies it as a hidden file).
Also, checking the manual page for find
on my system shows no --ignore
option.
That said, if you want to ignore any files with a .
in their name, you can use find
's -not
operator:
find -type f -not -name '*.*' -print
thanks but this doesn`t print anything.
– kutlus
30 mins ago
add a comment |
try
find . -type f ! -name '*.*' -print
where
!
: not (! must be escaped)
name '*.*'
: filename with extension
arg, not fast enough !!
– Archemar
51 mins ago
Having to escape!
is why I usually suggest using-not
.
– DopeGhoti
51 mins ago
well it work w/o escape, I've been escaping it ever since SunOS 3.X... sight.
– Archemar
50 mins ago
thanks but this doesn`t print anything.
– kutlus
31 mins ago
add a comment |
As other's have pointed out, "extensions" don't really mean anything to Unix systems. But we can remove them from a listing with a simple sed
command.
e.g.
find * -type f -print | sed 's/.[^.]*$//'
If there are directories and you don't want them to be shown in the listing then
find * -type f -printf "%fn" | sed 's/.[^.]*$//'
For a single directory we can just use ls
instead of find
ls | sed 's/.[^.]*$//'
add a comment |
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4 Answers
4
active
oldest
votes
4 Answers
4
active
oldest
votes
active
oldest
votes
active
oldest
votes
If I understand you correctly (I didn't, see second part of the answer), you want to avoid listing filenames that contain a dot character.
This will do that:
find . -type f ! -name '*.*'
The filename globbing pattern *.*
would match any filename containing at least one dot. The preceding !
negates the sense of the match, which means that the pathnames that gets through to the end will be those of files that have no dots in their names. In really ancient shells, you may want to escape the !
as !
(or update your Unix installation). The lone !
won't invoke bash
's history expansion facility.
To print only the filename component of the found pathname, with GNU find
:
find . -type f ! -name '*.*' -printf '%fn'
With standard find
(or GNU find
for that matter):
find . -type f ! -name '*.*' -exec basename {} ;
Before using this in a command substitution in a loop, see "Why is looping over find's output bad practice?".
To list all filenames, and at the same time remove everything after the last dot in the name ("remove the extension"), you may use
find . -type f -exec sh -c '
for pathname do
pathname=$( basename "$pathname" )
printf "%sn" "${pathname%.*}"
done' sh {} +
This would send all found pathnames of all files to a short shell loop. The loop would take each pathname and call basename
on it to extract the filename component of the pathname, and then print the resulting string with everything after the last dot removed.
The parameter expansion ${pathname%.*}
means "remove the shortest string matching .*
(a literal dot followed by arbitrary text) from the end of the value of $pathname
". It would have the effect of removing a filename suffix after the last dot in the filename.
For more info about find ... -exec ... {} +
, see e.g. "Understanding the -exec option of `find`".
Thanks for your help, I have tried all three, but they don't print anything. Am I missing something, on the same terminal, in the same directory find . -type f -printf '%fn' works but as I asked in the question I need them without extensions.
– kutlus
26 mins ago
@kutlus In that case, I (and the others) may have misunderstood your question. Do you want to remove everything after the last dot in the filename?
– Kusalananda
24 mins ago
I just want the file name, example; some files are myfile1.txt, myfile2.mp3, i want it prints myfile1, myfile2. sorry if my questions wasn`t clear, thanks
– kutlus
21 mins ago
@kutlus See updated answer.
– Kusalananda
17 mins ago
This worked, many thanks!
– kutlus
14 mins ago
add a comment |
If I understand you correctly (I didn't, see second part of the answer), you want to avoid listing filenames that contain a dot character.
This will do that:
find . -type f ! -name '*.*'
The filename globbing pattern *.*
would match any filename containing at least one dot. The preceding !
negates the sense of the match, which means that the pathnames that gets through to the end will be those of files that have no dots in their names. In really ancient shells, you may want to escape the !
as !
(or update your Unix installation). The lone !
won't invoke bash
's history expansion facility.
To print only the filename component of the found pathname, with GNU find
:
find . -type f ! -name '*.*' -printf '%fn'
With standard find
(or GNU find
for that matter):
find . -type f ! -name '*.*' -exec basename {} ;
Before using this in a command substitution in a loop, see "Why is looping over find's output bad practice?".
To list all filenames, and at the same time remove everything after the last dot in the name ("remove the extension"), you may use
find . -type f -exec sh -c '
for pathname do
pathname=$( basename "$pathname" )
printf "%sn" "${pathname%.*}"
done' sh {} +
This would send all found pathnames of all files to a short shell loop. The loop would take each pathname and call basename
on it to extract the filename component of the pathname, and then print the resulting string with everything after the last dot removed.
The parameter expansion ${pathname%.*}
means "remove the shortest string matching .*
(a literal dot followed by arbitrary text) from the end of the value of $pathname
". It would have the effect of removing a filename suffix after the last dot in the filename.
For more info about find ... -exec ... {} +
, see e.g. "Understanding the -exec option of `find`".
Thanks for your help, I have tried all three, but they don't print anything. Am I missing something, on the same terminal, in the same directory find . -type f -printf '%fn' works but as I asked in the question I need them without extensions.
– kutlus
26 mins ago
@kutlus In that case, I (and the others) may have misunderstood your question. Do you want to remove everything after the last dot in the filename?
– Kusalananda
24 mins ago
I just want the file name, example; some files are myfile1.txt, myfile2.mp3, i want it prints myfile1, myfile2. sorry if my questions wasn`t clear, thanks
– kutlus
21 mins ago
@kutlus See updated answer.
– Kusalananda
17 mins ago
This worked, many thanks!
– kutlus
14 mins ago
add a comment |
If I understand you correctly (I didn't, see second part of the answer), you want to avoid listing filenames that contain a dot character.
This will do that:
find . -type f ! -name '*.*'
The filename globbing pattern *.*
would match any filename containing at least one dot. The preceding !
negates the sense of the match, which means that the pathnames that gets through to the end will be those of files that have no dots in their names. In really ancient shells, you may want to escape the !
as !
(or update your Unix installation). The lone !
won't invoke bash
's history expansion facility.
To print only the filename component of the found pathname, with GNU find
:
find . -type f ! -name '*.*' -printf '%fn'
With standard find
(or GNU find
for that matter):
find . -type f ! -name '*.*' -exec basename {} ;
Before using this in a command substitution in a loop, see "Why is looping over find's output bad practice?".
To list all filenames, and at the same time remove everything after the last dot in the name ("remove the extension"), you may use
find . -type f -exec sh -c '
for pathname do
pathname=$( basename "$pathname" )
printf "%sn" "${pathname%.*}"
done' sh {} +
This would send all found pathnames of all files to a short shell loop. The loop would take each pathname and call basename
on it to extract the filename component of the pathname, and then print the resulting string with everything after the last dot removed.
The parameter expansion ${pathname%.*}
means "remove the shortest string matching .*
(a literal dot followed by arbitrary text) from the end of the value of $pathname
". It would have the effect of removing a filename suffix after the last dot in the filename.
For more info about find ... -exec ... {} +
, see e.g. "Understanding the -exec option of `find`".
If I understand you correctly (I didn't, see second part of the answer), you want to avoid listing filenames that contain a dot character.
This will do that:
find . -type f ! -name '*.*'
The filename globbing pattern *.*
would match any filename containing at least one dot. The preceding !
negates the sense of the match, which means that the pathnames that gets through to the end will be those of files that have no dots in their names. In really ancient shells, you may want to escape the !
as !
(or update your Unix installation). The lone !
won't invoke bash
's history expansion facility.
To print only the filename component of the found pathname, with GNU find
:
find . -type f ! -name '*.*' -printf '%fn'
With standard find
(or GNU find
for that matter):
find . -type f ! -name '*.*' -exec basename {} ;
Before using this in a command substitution in a loop, see "Why is looping over find's output bad practice?".
To list all filenames, and at the same time remove everything after the last dot in the name ("remove the extension"), you may use
find . -type f -exec sh -c '
for pathname do
pathname=$( basename "$pathname" )
printf "%sn" "${pathname%.*}"
done' sh {} +
This would send all found pathnames of all files to a short shell loop. The loop would take each pathname and call basename
on it to extract the filename component of the pathname, and then print the resulting string with everything after the last dot removed.
The parameter expansion ${pathname%.*}
means "remove the shortest string matching .*
(a literal dot followed by arbitrary text) from the end of the value of $pathname
". It would have the effect of removing a filename suffix after the last dot in the filename.
For more info about find ... -exec ... {} +
, see e.g. "Understanding the -exec option of `find`".
edited 14 mins ago
answered 53 mins ago
KusalanandaKusalananda
126k16239391
126k16239391
Thanks for your help, I have tried all three, but they don't print anything. Am I missing something, on the same terminal, in the same directory find . -type f -printf '%fn' works but as I asked in the question I need them without extensions.
– kutlus
26 mins ago
@kutlus In that case, I (and the others) may have misunderstood your question. Do you want to remove everything after the last dot in the filename?
– Kusalananda
24 mins ago
I just want the file name, example; some files are myfile1.txt, myfile2.mp3, i want it prints myfile1, myfile2. sorry if my questions wasn`t clear, thanks
– kutlus
21 mins ago
@kutlus See updated answer.
– Kusalananda
17 mins ago
This worked, many thanks!
– kutlus
14 mins ago
add a comment |
Thanks for your help, I have tried all three, but they don't print anything. Am I missing something, on the same terminal, in the same directory find . -type f -printf '%fn' works but as I asked in the question I need them without extensions.
– kutlus
26 mins ago
@kutlus In that case, I (and the others) may have misunderstood your question. Do you want to remove everything after the last dot in the filename?
– Kusalananda
24 mins ago
I just want the file name, example; some files are myfile1.txt, myfile2.mp3, i want it prints myfile1, myfile2. sorry if my questions wasn`t clear, thanks
– kutlus
21 mins ago
@kutlus See updated answer.
– Kusalananda
17 mins ago
This worked, many thanks!
– kutlus
14 mins ago
Thanks for your help, I have tried all three, but they don't print anything. Am I missing something, on the same terminal, in the same directory find . -type f -printf '%fn' works but as I asked in the question I need them without extensions.
– kutlus
26 mins ago
Thanks for your help, I have tried all three, but they don't print anything. Am I missing something, on the same terminal, in the same directory find . -type f -printf '%fn' works but as I asked in the question I need them without extensions.
– kutlus
26 mins ago
@kutlus In that case, I (and the others) may have misunderstood your question. Do you want to remove everything after the last dot in the filename?
– Kusalananda
24 mins ago
@kutlus In that case, I (and the others) may have misunderstood your question. Do you want to remove everything after the last dot in the filename?
– Kusalananda
24 mins ago
I just want the file name, example; some files are myfile1.txt, myfile2.mp3, i want it prints myfile1, myfile2. sorry if my questions wasn`t clear, thanks
– kutlus
21 mins ago
I just want the file name, example; some files are myfile1.txt, myfile2.mp3, i want it prints myfile1, myfile2. sorry if my questions wasn`t clear, thanks
– kutlus
21 mins ago
@kutlus See updated answer.
– Kusalananda
17 mins ago
@kutlus See updated answer.
– Kusalananda
17 mins ago
This worked, many thanks!
– kutlus
14 mins ago
This worked, many thanks!
– kutlus
14 mins ago
add a comment |
In Linux, there is no such thing as a file extension. A .
in a file name has no significance whatsoever (notwithstanding that a .
as the first character in a filename identifies it as a hidden file).
Also, checking the manual page for find
on my system shows no --ignore
option.
That said, if you want to ignore any files with a .
in their name, you can use find
's -not
operator:
find -type f -not -name '*.*' -print
thanks but this doesn`t print anything.
– kutlus
30 mins ago
add a comment |
In Linux, there is no such thing as a file extension. A .
in a file name has no significance whatsoever (notwithstanding that a .
as the first character in a filename identifies it as a hidden file).
Also, checking the manual page for find
on my system shows no --ignore
option.
That said, if you want to ignore any files with a .
in their name, you can use find
's -not
operator:
find -type f -not -name '*.*' -print
thanks but this doesn`t print anything.
– kutlus
30 mins ago
add a comment |
In Linux, there is no such thing as a file extension. A .
in a file name has no significance whatsoever (notwithstanding that a .
as the first character in a filename identifies it as a hidden file).
Also, checking the manual page for find
on my system shows no --ignore
option.
That said, if you want to ignore any files with a .
in their name, you can use find
's -not
operator:
find -type f -not -name '*.*' -print
In Linux, there is no such thing as a file extension. A .
in a file name has no significance whatsoever (notwithstanding that a .
as the first character in a filename identifies it as a hidden file).
Also, checking the manual page for find
on my system shows no --ignore
option.
That said, if you want to ignore any files with a .
in their name, you can use find
's -not
operator:
find -type f -not -name '*.*' -print
answered 52 mins ago
DopeGhotiDopeGhoti
44.3k55684
44.3k55684
thanks but this doesn`t print anything.
– kutlus
30 mins ago
add a comment |
thanks but this doesn`t print anything.
– kutlus
30 mins ago
thanks but this doesn`t print anything.
– kutlus
30 mins ago
thanks but this doesn`t print anything.
– kutlus
30 mins ago
add a comment |
try
find . -type f ! -name '*.*' -print
where
!
: not (! must be escaped)
name '*.*'
: filename with extension
arg, not fast enough !!
– Archemar
51 mins ago
Having to escape!
is why I usually suggest using-not
.
– DopeGhoti
51 mins ago
well it work w/o escape, I've been escaping it ever since SunOS 3.X... sight.
– Archemar
50 mins ago
thanks but this doesn`t print anything.
– kutlus
31 mins ago
add a comment |
try
find . -type f ! -name '*.*' -print
where
!
: not (! must be escaped)
name '*.*'
: filename with extension
arg, not fast enough !!
– Archemar
51 mins ago
Having to escape!
is why I usually suggest using-not
.
– DopeGhoti
51 mins ago
well it work w/o escape, I've been escaping it ever since SunOS 3.X... sight.
– Archemar
50 mins ago
thanks but this doesn`t print anything.
– kutlus
31 mins ago
add a comment |
try
find . -type f ! -name '*.*' -print
where
!
: not (! must be escaped)
name '*.*'
: filename with extension
try
find . -type f ! -name '*.*' -print
where
!
: not (! must be escaped)
name '*.*'
: filename with extension
answered 52 mins ago
ArchemarArchemar
19.9k93670
19.9k93670
arg, not fast enough !!
– Archemar
51 mins ago
Having to escape!
is why I usually suggest using-not
.
– DopeGhoti
51 mins ago
well it work w/o escape, I've been escaping it ever since SunOS 3.X... sight.
– Archemar
50 mins ago
thanks but this doesn`t print anything.
– kutlus
31 mins ago
add a comment |
arg, not fast enough !!
– Archemar
51 mins ago
Having to escape!
is why I usually suggest using-not
.
– DopeGhoti
51 mins ago
well it work w/o escape, I've been escaping it ever since SunOS 3.X... sight.
– Archemar
50 mins ago
thanks but this doesn`t print anything.
– kutlus
31 mins ago
arg, not fast enough !!
– Archemar
51 mins ago
arg, not fast enough !!
– Archemar
51 mins ago
Having to escape
!
is why I usually suggest using -not
.– DopeGhoti
51 mins ago
Having to escape
!
is why I usually suggest using -not
.– DopeGhoti
51 mins ago
well it work w/o escape, I've been escaping it ever since SunOS 3.X... sight.
– Archemar
50 mins ago
well it work w/o escape, I've been escaping it ever since SunOS 3.X... sight.
– Archemar
50 mins ago
thanks but this doesn`t print anything.
– kutlus
31 mins ago
thanks but this doesn`t print anything.
– kutlus
31 mins ago
add a comment |
As other's have pointed out, "extensions" don't really mean anything to Unix systems. But we can remove them from a listing with a simple sed
command.
e.g.
find * -type f -print | sed 's/.[^.]*$//'
If there are directories and you don't want them to be shown in the listing then
find * -type f -printf "%fn" | sed 's/.[^.]*$//'
For a single directory we can just use ls
instead of find
ls | sed 's/.[^.]*$//'
add a comment |
As other's have pointed out, "extensions" don't really mean anything to Unix systems. But we can remove them from a listing with a simple sed
command.
e.g.
find * -type f -print | sed 's/.[^.]*$//'
If there are directories and you don't want them to be shown in the listing then
find * -type f -printf "%fn" | sed 's/.[^.]*$//'
For a single directory we can just use ls
instead of find
ls | sed 's/.[^.]*$//'
add a comment |
As other's have pointed out, "extensions" don't really mean anything to Unix systems. But we can remove them from a listing with a simple sed
command.
e.g.
find * -type f -print | sed 's/.[^.]*$//'
If there are directories and you don't want them to be shown in the listing then
find * -type f -printf "%fn" | sed 's/.[^.]*$//'
For a single directory we can just use ls
instead of find
ls | sed 's/.[^.]*$//'
As other's have pointed out, "extensions" don't really mean anything to Unix systems. But we can remove them from a listing with a simple sed
command.
e.g.
find * -type f -print | sed 's/.[^.]*$//'
If there are directories and you don't want them to be shown in the listing then
find * -type f -printf "%fn" | sed 's/.[^.]*$//'
For a single directory we can just use ls
instead of find
ls | sed 's/.[^.]*$//'
answered 12 mins ago
Stephen HarrisStephen Harris
25.5k24477
25.5k24477
add a comment |
add a comment |
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StackExchange.helpers.onClickDraftSave('#login-link');
});
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StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
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Post as a guest
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StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
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Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
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