How to sort categorical values by an arbitrary order?












0















I have a table called ANIMALS which looks like this



| name      | category |
------------------------
| fluffer | CAT |
| tooter | ELEPHANT |
| tooter_jr | ELEPHANT |
| woofer | DOG |


If I sort the table by category then I will get all CATs then DOGs then ELEPHANTs. But I need to order the table such that the sequence is CAT > ELEPHANT > DOG



How can I achieve this result?










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  • Create a table (category - sorting weight) and use it in the query. Or use any trick (expression like ORDER BY INSTR('CAT,ELEPHANT,DOG', category,1,1)).

    – Akina
    16 hours ago


















0















I have a table called ANIMALS which looks like this



| name      | category |
------------------------
| fluffer | CAT |
| tooter | ELEPHANT |
| tooter_jr | ELEPHANT |
| woofer | DOG |


If I sort the table by category then I will get all CATs then DOGs then ELEPHANTs. But I need to order the table such that the sequence is CAT > ELEPHANT > DOG



How can I achieve this result?










share|improve this question























  • Create a table (category - sorting weight) and use it in the query. Or use any trick (expression like ORDER BY INSTR('CAT,ELEPHANT,DOG', category,1,1)).

    – Akina
    16 hours ago
















0












0








0








I have a table called ANIMALS which looks like this



| name      | category |
------------------------
| fluffer | CAT |
| tooter | ELEPHANT |
| tooter_jr | ELEPHANT |
| woofer | DOG |


If I sort the table by category then I will get all CATs then DOGs then ELEPHANTs. But I need to order the table such that the sequence is CAT > ELEPHANT > DOG



How can I achieve this result?










share|improve this question














I have a table called ANIMALS which looks like this



| name      | category |
------------------------
| fluffer | CAT |
| tooter | ELEPHANT |
| tooter_jr | ELEPHANT |
| woofer | DOG |


If I sort the table by category then I will get all CATs then DOGs then ELEPHANTs. But I need to order the table such that the sequence is CAT > ELEPHANT > DOG



How can I achieve this result?







oracle oracle-12c






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked 17 hours ago









Souradeep NandaSouradeep Nanda

395137




395137













  • Create a table (category - sorting weight) and use it in the query. Or use any trick (expression like ORDER BY INSTR('CAT,ELEPHANT,DOG', category,1,1)).

    – Akina
    16 hours ago





















  • Create a table (category - sorting weight) and use it in the query. Or use any trick (expression like ORDER BY INSTR('CAT,ELEPHANT,DOG', category,1,1)).

    – Akina
    16 hours ago



















Create a table (category - sorting weight) and use it in the query. Or use any trick (expression like ORDER BY INSTR('CAT,ELEPHANT,DOG', category,1,1)).

– Akina
16 hours ago







Create a table (category - sorting weight) and use it in the query. Or use any trick (expression like ORDER BY INSTR('CAT,ELEPHANT,DOG', category,1,1)).

– Akina
16 hours ago












1 Answer
1






active

oldest

votes


















1














This can be done using a CASE statement in the ORDER BY clause:



WITH
Animals (name, category) AS (
SELECT 'fluffer', 'CAT' FROM DUAL UNION ALL
SELECT 'tooter', 'ELEPHANT' FROM DUAL UNION ALL
SELECT 'tooter_jr', 'ELEPHANT' FROM DUAL UNION ALL
SELECT 'woofer', 'DOG' FROM DUAL
)
SELECT
name, category
FROM Animals
ORDER BY
CASE category
WHEN 'CAT' THEN 1
WHEN 'ELEPHANT' THEN 2
WHEN 'DOG' THEN 3
END
;


Please comment, if and as this requires adjustment / further detail.






share|improve this answer
























  • I am getting error: Error: ORA-00904: "DOG": invalid identifier I am still doing a little trial and error.

    – Souradeep Nanda
    16 hours ago











  • Oh ok. I was doing ``` ORDER BY CASE category WHEN ${TYPES.CAT} THEN 1 WHEN ${TYPES.ELEPHANT} THEN 2 WHEN ${TYPES.DOG} THEN 3 END ; ``` instead of ``` ORDER BY CASE category WHEN '${TYPES.CAT}' THEN 1 WHEN '${TYPES.ELEPHANT}' THEN 2 WHEN '${TYPES.DOG}' THEN 3 END ; ```

    – Souradeep Nanda
    16 hours ago











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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









1














This can be done using a CASE statement in the ORDER BY clause:



WITH
Animals (name, category) AS (
SELECT 'fluffer', 'CAT' FROM DUAL UNION ALL
SELECT 'tooter', 'ELEPHANT' FROM DUAL UNION ALL
SELECT 'tooter_jr', 'ELEPHANT' FROM DUAL UNION ALL
SELECT 'woofer', 'DOG' FROM DUAL
)
SELECT
name, category
FROM Animals
ORDER BY
CASE category
WHEN 'CAT' THEN 1
WHEN 'ELEPHANT' THEN 2
WHEN 'DOG' THEN 3
END
;


Please comment, if and as this requires adjustment / further detail.






share|improve this answer
























  • I am getting error: Error: ORA-00904: "DOG": invalid identifier I am still doing a little trial and error.

    – Souradeep Nanda
    16 hours ago











  • Oh ok. I was doing ``` ORDER BY CASE category WHEN ${TYPES.CAT} THEN 1 WHEN ${TYPES.ELEPHANT} THEN 2 WHEN ${TYPES.DOG} THEN 3 END ; ``` instead of ``` ORDER BY CASE category WHEN '${TYPES.CAT}' THEN 1 WHEN '${TYPES.ELEPHANT}' THEN 2 WHEN '${TYPES.DOG}' THEN 3 END ; ```

    – Souradeep Nanda
    16 hours ago
















1














This can be done using a CASE statement in the ORDER BY clause:



WITH
Animals (name, category) AS (
SELECT 'fluffer', 'CAT' FROM DUAL UNION ALL
SELECT 'tooter', 'ELEPHANT' FROM DUAL UNION ALL
SELECT 'tooter_jr', 'ELEPHANT' FROM DUAL UNION ALL
SELECT 'woofer', 'DOG' FROM DUAL
)
SELECT
name, category
FROM Animals
ORDER BY
CASE category
WHEN 'CAT' THEN 1
WHEN 'ELEPHANT' THEN 2
WHEN 'DOG' THEN 3
END
;


Please comment, if and as this requires adjustment / further detail.






share|improve this answer
























  • I am getting error: Error: ORA-00904: "DOG": invalid identifier I am still doing a little trial and error.

    – Souradeep Nanda
    16 hours ago











  • Oh ok. I was doing ``` ORDER BY CASE category WHEN ${TYPES.CAT} THEN 1 WHEN ${TYPES.ELEPHANT} THEN 2 WHEN ${TYPES.DOG} THEN 3 END ; ``` instead of ``` ORDER BY CASE category WHEN '${TYPES.CAT}' THEN 1 WHEN '${TYPES.ELEPHANT}' THEN 2 WHEN '${TYPES.DOG}' THEN 3 END ; ```

    – Souradeep Nanda
    16 hours ago














1












1








1







This can be done using a CASE statement in the ORDER BY clause:



WITH
Animals (name, category) AS (
SELECT 'fluffer', 'CAT' FROM DUAL UNION ALL
SELECT 'tooter', 'ELEPHANT' FROM DUAL UNION ALL
SELECT 'tooter_jr', 'ELEPHANT' FROM DUAL UNION ALL
SELECT 'woofer', 'DOG' FROM DUAL
)
SELECT
name, category
FROM Animals
ORDER BY
CASE category
WHEN 'CAT' THEN 1
WHEN 'ELEPHANT' THEN 2
WHEN 'DOG' THEN 3
END
;


Please comment, if and as this requires adjustment / further detail.






share|improve this answer













This can be done using a CASE statement in the ORDER BY clause:



WITH
Animals (name, category) AS (
SELECT 'fluffer', 'CAT' FROM DUAL UNION ALL
SELECT 'tooter', 'ELEPHANT' FROM DUAL UNION ALL
SELECT 'tooter_jr', 'ELEPHANT' FROM DUAL UNION ALL
SELECT 'woofer', 'DOG' FROM DUAL
)
SELECT
name, category
FROM Animals
ORDER BY
CASE category
WHEN 'CAT' THEN 1
WHEN 'ELEPHANT' THEN 2
WHEN 'DOG' THEN 3
END
;


Please comment, if and as this requires adjustment / further detail.







share|improve this answer












share|improve this answer



share|improve this answer










answered 16 hours ago









AbeceeAbecee

31613




31613













  • I am getting error: Error: ORA-00904: "DOG": invalid identifier I am still doing a little trial and error.

    – Souradeep Nanda
    16 hours ago











  • Oh ok. I was doing ``` ORDER BY CASE category WHEN ${TYPES.CAT} THEN 1 WHEN ${TYPES.ELEPHANT} THEN 2 WHEN ${TYPES.DOG} THEN 3 END ; ``` instead of ``` ORDER BY CASE category WHEN '${TYPES.CAT}' THEN 1 WHEN '${TYPES.ELEPHANT}' THEN 2 WHEN '${TYPES.DOG}' THEN 3 END ; ```

    – Souradeep Nanda
    16 hours ago



















  • I am getting error: Error: ORA-00904: "DOG": invalid identifier I am still doing a little trial and error.

    – Souradeep Nanda
    16 hours ago











  • Oh ok. I was doing ``` ORDER BY CASE category WHEN ${TYPES.CAT} THEN 1 WHEN ${TYPES.ELEPHANT} THEN 2 WHEN ${TYPES.DOG} THEN 3 END ; ``` instead of ``` ORDER BY CASE category WHEN '${TYPES.CAT}' THEN 1 WHEN '${TYPES.ELEPHANT}' THEN 2 WHEN '${TYPES.DOG}' THEN 3 END ; ```

    – Souradeep Nanda
    16 hours ago

















I am getting error: Error: ORA-00904: "DOG": invalid identifier I am still doing a little trial and error.

– Souradeep Nanda
16 hours ago





I am getting error: Error: ORA-00904: "DOG": invalid identifier I am still doing a little trial and error.

– Souradeep Nanda
16 hours ago













Oh ok. I was doing ``` ORDER BY CASE category WHEN ${TYPES.CAT} THEN 1 WHEN ${TYPES.ELEPHANT} THEN 2 WHEN ${TYPES.DOG} THEN 3 END ; ``` instead of ``` ORDER BY CASE category WHEN '${TYPES.CAT}' THEN 1 WHEN '${TYPES.ELEPHANT}' THEN 2 WHEN '${TYPES.DOG}' THEN 3 END ; ```

– Souradeep Nanda
16 hours ago





Oh ok. I was doing ``` ORDER BY CASE category WHEN ${TYPES.CAT} THEN 1 WHEN ${TYPES.ELEPHANT} THEN 2 WHEN ${TYPES.DOG} THEN 3 END ; ``` instead of ``` ORDER BY CASE category WHEN '${TYPES.CAT}' THEN 1 WHEN '${TYPES.ELEPHANT}' THEN 2 WHEN '${TYPES.DOG}' THEN 3 END ; ```

– Souradeep Nanda
16 hours ago


















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